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3 years ago

Gravity is an example of which type of force?

Chemistry

1 answer:

GuDViN [60]3 years ago

3 0

Answer:

attractive force

Explanation:

hope this helps, pls mark brainliest :D

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Consider the reaction below. HI + H2O mc014-1.jpg H3O+ + I– Which is an acid-conjugate base pair? HI and H2O H2O and H3O+ H3O+ a

lesya692 [45]

Answer: Option (d) is the correct answer.

Explanation:

According to Bronsted-Lowry, species which donate a proton are known as acid. The species which accept a proton are known as a base.

In the given reaction, acids and bases are as follows.

HI + $H_{2}O$ $\rightarrow$ $H_{3}O^{+}$ + $I^{-}$

Acid Base Conjugate acid Conjugate base

Therefore, the acid HI loses a proton to form a conjugate base that is $I^{-}$ .

Thus, we can conclude that HI and $I^{-}$ is an acid conjugate base pair.

4 0

3 years ago

Read 2 more answers

The measurement 1.00540 g contains significant figures. * 10 3 4 5 O 6

antiseptic1488 [7]

It contains 6 sig figs

4 0

3 years ago

A bowling ball is pushed with a force of 22.0 N and accelerates at 5.5 m/s^2 what is the mass of the bowling ball?

Kruka [31]

Data:

F (force) = 22.0 N

m (mass) = ? (in Kg)

a (acceleration) = 5.5 m/s²

We apply the data to the Resultant Force formula, we have:

4.0 kg

I hope this helps. =)

7 0

3 years ago

H2 + NO → H2O + N2 If 180.5 grams of N2 are produced, how many grams of H2 were reacted?

Lena [83]

Answer:

12.89 moles

Explanation:

Before we solve the question, we have to balance the equation of the reaction first. The balanced reaction will be:

2 NO + 2 H2→ N2 + 2 H2O

There are 180.5g of N2 produced, the number of produced in moles will be: 180.5g / (28g/mol)= 6.446 moles

The coefficient of H2 is two and the coefficient of N2 is one. Mean that we need two moles of H2 for every one mole of N2 produced. The number of H2 reacted will be: 2/1 * 6.446 moles = 12.89 moles

6 0

3 years ago

Given the wavelength of the corresponding emission line, calculate the equivalent radiated energy from n = 4 to n = 2 in both jo

lions [1.4K]

Explanation:

It is given that,

Initial orbit of electrons, $n_i=4$

Final orbit of electrons, $n_f=2$

We need to find energy, wavelength and frequency of the wave.

When atom make transition from one orbit to another, the energy of wave is given by :

$E=-13.6(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})$

Putting all the values we get :

$E=-13.6(\dfrac{1}{(4)^2}-\dfrac{1}{(2)^2})\\\\E=2.55\ eV$

We know that : $1\ eV=1.6\times 10^{-19}\ J$

So,

$E=2.55\times 1.6\times 10^{-19}\\\\E=4.08\times 10^{-19}\ J$

Energy of wave in terms of frequency is given by :

$E=hf$

$f=\dfrac{E}{h}\\\\f=\dfrac{4.08\times 10^{-19}}{6.63\times 10^{-34}}\\\\f=6.14\times 10^{14}\ Hz$

Also, $c=f\lambda$

$\lambda$ is wavelength

So,

$\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{6.14\times 10^{14}}\\\\\lambda=4.88\times 10^{-7}\ m\\\\\lambda=488\ nm$

Hence, this is the required solution.

4 0

3 years ago