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Mariana [72]
3 years ago
15

Now if your lab partner determined that there were 1.552 x 1022 atoms of H in an unknown sample of C2H4Cl2, how many milligrams

would the unknown sample weigh? 
There was 0.56 moles of H from the first question. 
Chemistry
1 answer:
STALIN [3.7K]3 years ago
3 0
To determine the mass of the sample in milligrams in this problem, we use the avogadro's number to convert from atoms to moles, relate the moles of element in the sample to the mole present and the molar mass of the sample. We do as follows:

1.552 x 10^22 atoms H ( 1 mol H / 6.022x10^23 atoms H ) ( 1 mol C2H4Cl2 / 4 mol H ) ( 98.96 g C2H4Cl2 / 1 mol C2H4Cl2 ) = 0.625 g C2H4Cl2 = 625 mg <span>C2H4Cl2</span>
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Use the following equation to answer the questions below:
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Explanation:

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Be + 2HCl → BeCl2 + H2

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1 mol of Be produces 1 mol of BeCl2

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1 mol of H2 is produced alongside 1 mol of BeCl2

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0.3128 mol of H2 would also be produced alongside 0.3128 mol of BeCl2

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