Answer:- Volume of the gas in the flask after the reaction is 156.0 L.
Solution:- The balanced equation for the combustion of ethane is:
From the balanced equation, ethane and oxygen react in 2:7 mol ratio or 2:7 volume ratio as we are assuming ideal behavior.
Let's see if any one of them is limiting by calculating the required volume of one for the other. Let's say we calculate required volume of oxygen for given 36.0 L of ethane as:
= 126 L 
126 L of oxygen are required to react completely with 36.0 L of ethane but only 105.0 L of oxygen are available, It means oxygen is limiting reactant.
let's calculate the volumes of each product gas formed for 105.0 L of oxygen as:
= 60.0 L 
Similarly, let's calculate the volume of water vapors formed:
= 90.0 L 
Since ethane is present in excess, the remaining volume of it would also be present in the flask.
Let's first calculate how many liters of it were used to react with 105.0 L of oxygen and then subtract them from given volume of ethane to know it's remaining volume:
= 30.0 L 
Excess volume of ethane = 36.0 L - 30.0 L = 6.0 L
Total volume of gas in the flask after reaction = 6.0 L + 60.0 L + 90.0 L = 156.0 L
Hence. the answer is 156.0 L.
Answer:
Explained below.
Explanation:
What has changed in the atmosphere is that oxidation has occurred where an oxidizing chemical specie has reacted with an oxygen containing compound.
Now these chemicals when they react with rain and fall on rocks react with the rocks to weaken them in a process known as chemical weathering.
Now when this weathering from the oxidizing chemicals from the rain react with rocks that contain iron, it leads to the rock having an appearance of rust.
Answer:
The substances in a mixture can be separated using physical methods such as filtration, freezing, and distillation.
There is little, see Enthalpy of mixing, or no energy change when a mixture forms.
Mixtures have variable compositions, while compounds have a fixed, definite formula.
Explanation:
Answer:
See explanation below
Explanation:
When the bromine (Br₂) reacts in presence of FeBr₃ with the isopropylbenzene, the isopropylbenzene is a ring activator, therefore, it will promote the substitution in the ortho and para positions. However, as the Isopropyl is voluminic, the ortho position would have steric hindrance and hence, this product is not formed in greater proportions. Instead, the para position becomes more available to reaction, and this product is formed in majority.
The mechanism of reaction can be seen in the following picture, along with the products of the reaction
Hope this helps
Hey there!
B + O₂ → B₂O₃
Balance O.
2 on the left, 3 on the right. Add a coefficient of 3 in front of O₂ and a coefficient of 2 in front of B₂O₃.
B + 3O₂ → 2B₂O₃
Balance B.
1 on the left, 4 on the right. Add a coefficient of 4 in front of B.
4B + 3O₂ → 2B₂O₃
Our final balanced equation: 4B + 3O₂ → 2B₂O₃
Hope this helps!
