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Charra [1.4K]
1 year ago
15

What must be true for line EF to not intersect plane L?

Mathematics
1 answer:
aev [14]1 year ago
5 0

Answer:

If line EF is parallel to line CD, it will not intersect plane L.

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A bin contains seven red chips, nine green chips, three yellow chips, and six blue chips. Find the probability of drawing a yell
igomit [66]

Answer:

a) 3/100

Step-by-step explanation:

There are 25 total chips

P(Yellow) = 3/25

With no replacement P(Blue) = 6/24 = 1/4

Multiply 3/25* 1/4= 3/100

3 0
3 years ago
Please help plz and explain
Liono4ka [1.6K]

Answer:

letter d or b

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8 0
3 years ago
HELPPPP ASAP PLEASE!!!!
wlad13 [49]

Answer:

the answer is C

Step-by-step explanation:

7 0
2 years ago
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suppose X and Y are independent random variables, both with normal distributions. If X has a mean of 45 with a standard deviatio
djyliett [7]

Answer:

0.9772 = 97.72% probability that a randomly generated value of X is greater than a randomly generated value of Y

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu_X = 45, \sigma_X = 4, \mu_Y = 35, \sigma_Y = 3

What is the probability that a randomly generated value of X is greater than a randomly generated value of Y

This means that the subtraction of X by Y has to be positive.

When we subtract two normal variables, the mean is the subtraction of their means, and the standard deviation is the square root of the sum of their variances. So

\mu = \mu_X - \mu_Y = 45 - 35 = 0

\sigma = \sqrt{\sigma_X^2+\sigma_Y^2} = \sqrt{25} = 5

We want to find P(X > 0), that is, 1 subtracted by the pvalue of Z when X = 0. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0 - 10}{5}

Z = -2

Z = -2 has a pvalue of 0.0228

1 - 0.0228 = 0.9772

0.9772 = 97.72% probability that a randomly generated value of X is greater than a randomly generated value of Y

4 0
3 years ago
Simplify expression<br> -9b-4+4+9b
Rasek [7]
B=0 because everything cancels out
3 0
3 years ago
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