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otez555 [7]
1 year ago
4

An electron starts at rest and accelerates through an electric field established by a set of parallel plates with a potential di

fference of 35 v. what is the speed of the electron the instant before it hits the negative plate? (e = 1.6 × 10-19 c, melectron = 9.1 × 10-31 kg)
Physics
1 answer:
Lana71 [14]1 year ago
7 0

The speed of the electron the instant before it hits the negative plate is v = 3.5 * 10^6 m/s.

<h3>What is Capacitor?</h3>

In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component.

Capacitance refers to a capacitor's effect. While there is some capacitance between any two nearby electrical wires in a circuit, a capacitor is a component made to increase capacitance. The term "condenser" or "condensator" originally applied to the capacitor. Condenser microphones, sometimes known as capacitor microphones, are a remarkable exception to the general lack of usage of this word and its cognates in English.

energy in Joules = charge in Coulombs * Potential difference in Volts

= 1.6 * 10^-19 * 35 = 56 * 10^-19 Joules

so,

(1/2) m v^2 = 56 * 10^-19

(1/2)(9.1*10^-31) v^2 = 56 * 10^-19

v^2 = 12.3 * 10^12

v = 3.5 * 10^6 m/s

to learn more about capacitor go to - brainly.com/question/14883923

#SPJ4

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g suppose he used an alpha particle with an energy of 8.3 MeV, what would be the speed of this alpha particle
mixas84 [53]

Answer:

<em>speed of the alpha particle is 2 x 10^7 m/s.</em>

Explanation:

energy of alpha particle = 8.3 Mev

1 Mev = 1.602 x 10^-13 J

8.3 Mev = x

solving, x = 8.3 x 1.602 x 10^-13 = 1.329 x 10^-12 J

mass of a alpha particle = 6.645 x 10^−27 kg

The energy of the alpha particle is the kinetic energy KE of the alpha particle

KE = \frac{1}{2}mv^{2}

where m is the mass of the alpha particle

v is  the velocity of the alpha particle

substituting values, we have

1.329 x 10^-12 = \frac{1}{2}*6.645*10^{-27}*v^{2}

v^{2} = 4 x 10^14

v = \sqrt{4*10^{14} } = <em>2 x 10^7 m/s</em>

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All matter we encounter in everyday life exists in one of three physical formss True or False.
gayaneshka [121]

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To convert minutes per second into kilometre per hour we multiply the speed with​
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To convert m/sec into km/hr, multiply the number by 18 and then divide it by 5.

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Which characteristic must a food have to receive a “natural” label from the FDA ?
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No artificial ingredients
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4 years ago
A car slows down at -5.00 m/s² until it comes to a stop after travelling 15.0 m. What was the initial speed of the car?
lapo4ka [179]
<h2>Answer: 12.24m/s</h2>

According to <u>kinematics</u> this situation is described as a uniformly accelerated rectilinear motion. This means the acceleration while the car is in motion is constant.

Now, among the equations related to this type of motion we have the following that relates the velocity with the acceleration and the distance traveled:

V_{f}^{2}-V_{o}^{2}=2.a.d   (1)

Where:

V_{f} is the Final Velocity of the car. We are told "the car comes to a stop after travelling", this means it is 0.

V_{o} is the Initial Velocity, the value we want to find

a is the constant acceleration of the car (the negative sign means the car is decelerating)

d is the distance traveled by the car

Now, let's substitute the known values in equation (1) and find V_{o}:

0-V_{o}^{2}=2(-5m/{s}^{2})(15m)    (2)

-V_{o}^{2}=-150{m}^{2}/{s}^{2}    (3)

Multiplying by -1 on both sides of the equation:

V_{o}^{2}=150{m}^{2}/{s}^{2}    (4)

V_{o}=\sqrt{150{m}^{2}/{s}^{2}}    (5)

Finally:

V_{o}=12.24m/s >>>This is the Initial velocity of the car

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3 years ago
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