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Hoochie [10]
3 years ago
12

A wheelbarrow is a good example of a second-class lever. True or False

Physics
1 answer:
olganol [36]3 years ago
3 0

Answer:

true

Explanation:

a wheelbarrow has its load situated between the fulcrum and the force the wheel Barrow is 2nd class because of its resistance between the force and the axis

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A rocket moves upward from rest with an acceleration of 40 m/s2 for 5 seconds. It then runs out of fuel and continues to move up
Snezhnost [94]

Answer:

Maximum height of rocket  = 2538.74 m

Explanation:

We have equation of motion s = ut + 0.5 at²

For first 5 seconds

          s = 0 x 5 + 0.5 x 40 x 5² = 500 m

Now let us find out time after 5 seconds rocket move upward.

We have the equation of motion v = u + at

After 5 seconds velocity of rocket

         v = 0 + 40 x 5 = 200 m/s

After 5 seconds the velocity reduces 9.8m/s per second due to gravity.

Time of flying after 5 seconds

          t=\frac{200}{9.81}=20.38s

Distance traveled in this 20.38 s

          s = 200 x 20.38 - 0.5 x 9.81 x 20.38² = 2038.74 m

Maximum height of rocket = 500 +2038.74 = 2538.74 m

6 0
3 years ago
Does groundwater flow or stay still?
zhenek [66]

Answer:

yes it flows through flow paths.

Explanation:

5 0
3 years ago
You are in the forest with some of your friends. You’re being chased by a very angry and hungry bear.
melomori [17]

Answer:

2m head start or else you done for

Explanation:

you cant even out run a bear they run at 35mph the fastest human is 25

8 0
3 years ago
Provided the amplitude is sufficiently great, the human ear can respond to longitudinal waves over a range of frequencies from a
riadik2000 [5.3K]

Answer:

Check the explanation

Explanation:

The beat frequency is

df = f2 - f1

the wavelength is

lamda1 = (v/f1)

and lamda2 = (v/f2)

where v = 340 m/s,f1 = 25.0 kHz and f2 = 20.0 kHz

8 0
3 years ago
An object with a mass of 78kg is lifted through a height of 6 meters. How much work is done?
g100num [7]
Work = force x distance. 

force = mass x acceleration 

work = mass x acceleration x diastance 

use acceleration of gravity in this problem 

W (J) = m (kg) x a (m/s/s) x d (m) 
W = 78 x 9.8 x 6 
W = 4586.4

3 0
3 years ago
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