Answer:
No Time
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Answer:
19.6 m/s
Explanation:
The parameters given are:
Mass M = 20 Kg
Force F = 285 N
Angle Ø = 30 degree
Time t = 4 seconds
Coefficient of friction = 0.72
At the plane, the weight of the box will be mgsinØ
Resolving forces at the plane, we will have:
MgsinØ + Fr = F
Where Fr = frictional force.
Fr = F - mgsinØ
Substitute all the parameters into the formula
Fr = 285 - 20 × 9.8 sin30
Fr = 285 - 98
Fr = 187 N
But for the box moving toward the top of the plane,
F - Fr = ma
Where a = V/t
Substitute all the parameters involved into the formula
285 - 187 = 20 ( V/4)
98 = 5V
V = 98/5
V = 19.6 m/s
Therefore, the speed with which the box is moving is 19.6 m/s
Answer:
C 3.6 cm, 56 degrees North of the East axis
Explanation:
The two vectors are perpendicular to each other, so we can find the magnitude of their resultant simply by using the Pythagorean theorem:

where
A = 2.0 cm is the magnitude of the first vector
B = 3.0 cm is the magnitude of the second vector
Substituting,

Now we have to find the angle. If we measure the angle as North of East, the tangent of the angle is equal to the ratio between the component along North and the component along East. Therefore, in this case:

So, 56 degrees North of East.
Answer:

Explanation:
Let suppose that centrifuge is rotating at constant angular speed, which means that resultant acceleration is equal to radial acceleration at given radius, whose formula is:

Where:
- Angular speed, measured in radians per second.
- Radius of rotation, measured in meters.
The angular speed is first determined:

Where
is the angular speed, measured in revolutions per minute.
If
, the angular speed measured in radians per second is:


Now, if
and
, the resultant acceleration is then:


If gravitational acceleration is equal to 9.807 meters per square second, then the radial acceleration is equivalent to 1006.382 times the gravitational acceleration. That is:
