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Juliette [100K]
3 years ago
9

Explain, in terms of electrons, why the radius of a potassium atom is larger than the radius of a potassium ion in the ground st

ate.
Chemistry
1 answer:
barxatty [35]3 years ago
4 0
Because the Potassium ion loses an electron, the electrons come a little closer to the nucleus because they are attracted to the protons. This makes the ion smaller in radius
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3 years ago
Used in preparation of fertilizer​
boyakko [2]

Answer:

SO SORRY IF THIS IS WRONG BUT I HOPE THIS HELPS

Explanation:

Primary fertilizers include substances derived from nitrogen, phosphorus, and potassium. Various raw materials are used to produce these compounds. ... The phosphorus component is made using sulfur, coal, and phosphate rock. The potassium source comes from potassium chloride, a primary component of potash.

3 0
3 years ago
Read 2 more answers
How will the rate at which a solid solute dissolves change if the solution is stirred?
MakcuM [25]

Answer:

The rate at which the solute dissolves will increase.

Explanation:

If a solution is stirred, the rate at which a solute dissolves would increase substantially provided the solution is not yet saturated.

Stiring would cause more of the solution to come in contact with every part of the solute. It will increase the surface area of contact for the solution to act which will shoot up the rate of reaction. Stiring helps to bring solutes in solutions into a more close contact with the molecules or compounds of the medium.

6 0
3 years ago
What is the molality of a solution of water and kcl if the freezing point of the solution is –3mc030-1.jpgc?
Natasha_Volkova [10]
We will use the expression for freezing point depression ∆Tf
     ∆Tf = i Kf m
Since we know that the freezing point of water is 0 degree Celsius, temperature change ∆Tf is 
     ∆Tf = 0C - (-3°C) = 3°C 
and the van't Hoff Factor i is approximately equal to 2 since one molecule of KCl in aqueous solution will produce one K+ ion and  one Cl- ion:
     KCl → K+ + Cl- 
Therefore, the molality m of the solution can be calculated as 
     3 = 2 * 1.86 * m
     m = 3 / (2 * 1.86)
     m = 0.80 molal
4 0
3 years ago
What fraction of a sample of 6832ge, whose half-life is about 9 months, will remain after 2.9 yr ?
Viefleur [7K]
<span>The half-life of 9 months is 0.75 years. 2.0 years is 2.0/0.75 = 2.67 half-lives. Each half-life represents a reduction in the amount remaining by a factor of two, so: A(t)/A(0) = 2^(-t/h) where A(t) = amount at time t h = half-life in some unit t = elapsed time in the same unit A(t)/A(0) = 2^(-2.67) = 0.157 15.7% of the original amount will remain after 2.0 years. This is pretty easy one to solve. I was happy doing it.</span>
4 0
4 years ago
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