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nydimaria [60]
2 years ago
9

What will be the ph of a buffer solution containing an acid of pka7. 5, with an acid concentration exactly one fourth of that of

the conjugate base?
Chemistry
1 answer:
Lilit [14]2 years ago
5 0

The pH of a buffer solution containing acid of pKa 7.5 will be 8.1.

The pH of a solution indicates its acidity or basicity. A pH below 7 is acidic, while pH above 7 is basic. 7 is considered as the neutral value.

A buffer is a solution that has the ability to resist the change in pH when an acid or a base is added to it. The natural example of buffer is blood.

According to the question, pKa of acid = 7.5

If concentration of base is x then, concentration of acid will be x/4.

According to the Henderson–Hasselbalch equation,

pH = pKa + log [A⁻] / [HA]

pH = 7.5 + log [\frac{x}{x/4}]

pH = 7.5 + log 4 ⇒ 7.5 + 0.602

pH = 8.1

To know more about buffer, here

brainly.com/question/22821585

#SPJ4

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What is the most likely reason a computer model is used for a black hole?
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Answer:

Black holes are merely the most exotic example of the general principle that ... quantum computer stores bits on protons and uses magnetic fields to flip them. ... Powered by Standard Model software, the universe computes

Explanation:because they are mostly exotic

6 0
3 years ago
Given these reactions, where X represents a generic metal or metalloid 1) H2(g)+12O2(g)⟶H2O(g)ΔH1=−241.8 kJ 1) H2(g)+12O2(g)⟶H2O
Bond [772]

Answer:

ΔH = -793,6 kJ

Explanation:

It is possible to obtain ΔH of this reaction using Hess's law that says you can sum the half-reactions ΔH to obtain the ΔH of the global reaction:

If half-reactions are:

1) H₂(g) + ¹/₂O₂(g) ⟶ H₂O(g) ΔH₁ = −241.8 kJ

2) X(s) + 2Cl₂(g) ⟶ XCl₄(s) ΔH₂ = +356.9 kJ  

3) ¹/₂H₂(g) + ¹/₂Cl₂(g) ⟶ HCl(g) ΔH₃ = −92.3 kJ

4) X(s) + O₂(g) ⟶ XO₂(s) ΔH₄ = −639.1 kJ

5) H₂O(g) ⟶ H₂O(l) ΔH₅ = −44.0 kJ

The sum of (4) + 4×(3) - (2) - 2×(1) - 2×(5) is:

(4) X(s) + O₂(g) ⟶ XO₂(s) ΔH = −639.1 kJ

+4×(3) 2H₂(g) + 2Cl₂(g) ⟶ 4HCl(g) ΔH = −369,2 kJ

-(2) XCl₄(s) ⟶ X(s) + 2Cl₂(g) ΔH = -356,9 kJ

-2×(1) 2H₂O(g) ⟶ 2H₂(g) + O₂(g) ΔH = +483,6 kJ

-2×(5) 2H₂O(l) ⟶ 2H₂O(g) ΔH = +88.0 kJ

= <em>XCl₄(s) + 2H₂O(l) ⟶ XO₂(s) + 4HCl(g)</em>

Where ΔH is:

ΔH = -639,1 kJ -369,2 kJ -356,9 kJ +483,6 kJ +88,0 kJ

<em>ΔH = -793,6 kJ</em>

I hope it helps!

5 0
3 years ago
Consider the chemical equation below.
Aleks [24]
I would say A but then again im not too sure so hope that makes it easier to somehow
6 0
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How might the hydrosphere affect the biosphere?
iragen [17]

THE ANSWER IS OPTION B.

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HOPE THIS HELP

\small \color{gold}{ \underline{ \tt \bold \pink{ \: by:MissS3xy}}}

4 0
3 years ago
What is the formula for the aqueous salt produced when hydroiodic acid is neutralized by potassium hydroxide?
coldgirl [10]

Answer:

KOH(aq) + HCI(aq)  ----->  KCI(aq )+ H2O

base          acid               salt          water

hope this helps :)

Explanation:

5 0
4 years ago
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