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makkiz [27]
3 years ago
6

Temperature is used to measure the movement of particles such as atoms and molecules. as temperature increases, what is true of

the particles in a substance?
Chemistry
1 answer:
ad-work [718]3 years ago
8 0
The particles within the substance will sped up and expand.
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Transform boundaries are places where plates slide sideways past each other. At transform boundaries lithosphere is neither created nor destroyed. Many transform boundaries are found on the sea floor, where they connect segments of diverging mid-ocean ridges. California's San Andreas fault is a transform boundary. So its true
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3 years ago
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1. How many Chromium atoms are found in 25.8 milligrams of Chromium?​
givi [52]

Answer: 51.9961 g/mol, don't know if it helps :)

Explanation:

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A certain electrolyte solution contains 1 gram of salt for every 8 grams of sugar and every 200 grams of water. If the sugar to
12345 [234]

Answer:

The resulting solution contains approximately 666 g of water.

Explanation:

In the initial solution we have:

1g salt : 8g sugar : 200g water

This means that the ratios are:

\frac{salt}{sugar}  = \frac{1}{8} \\\\\frac{sugar}{water} = \frac{8}{200} =\frac{1}{25}

In the final solution we have:

5g salt: xg sugar: yg water

The new ratios are:

\frac{salt}{sugar} = \frac{3}{8} \\\\\frac{sugar}{water} = \frac{1}{50}

Now we can calculate the amount of sugar in the final solution:

\frac{salt}{sugar}  = \frac{5}{x} =\frac{3}{8} \\\\X = 13.333 g

Finally, we calculate the amount of water:

\frac{sugar}{water} = \frac{13.333}{y} = \frac{1}{50} \\y = 666.667 g

4 0
3 years ago
According to the work principle, the ration of work output to work input is always _____.
vekshin1

Answer:

less than one.

Explanation:

5 0
3 years ago
In a titration experiment 12.5 ml of 0.500 m h2so4 neutralized 50.0 ml of naoh. the concentration of the naoh solution is ____.
s344n2d4d5 [400]

0.250 mol/L

<em>Step 1</em>. Write the chemical equation

H2SO4 + 2NaOH → Na2SO4 + 2H2O

<em>Step 2</em>. Calculate the moles of H2SO4

Moles of H2SO4 = 12.5 mL H2SO4 × (0.500 mmol H2SO4/1 mL H2SO4)

= 6.25 mmol H2SO4

<em>Step 3</em>. Calculate the moles of NaOH

Moles of NaOH = 6.25 mmol H2SO4 × (2 mmol NaOH/(1 mmol H2SO4)

= 12.5 mmol NaOH

<em>Step 4</em>. Calculate the concentration of the NaOH

[NaOH] = moles/litres = 12.5 mmol/50.0 mL = 0.250 mol/L

4 0
3 years ago
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