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OverLord2011 [107]
1 year ago
6

Find the zeros x^4-2x^3-44x^2-88x-32

Mathematics
1 answer:
nekit [7.7K]1 year ago
4 0

The zeros which are the roots of the polynomial expressions are:

x = -4; x = - 2;  x = 4 - 2√5;  x = 2(2 + √5)

<h3>What are the zeros of a polynomial expression?</h3>

The zeros of a polynomial f(x) are really the values of x that answer the equation f(x) = 0. Thus, f(x) is a function of x, and the polynomial zeros refer to the values of x, which makes the f(x) value equal to zero. The digit of zeros in a polynomial is decided by the degree of equation f(x) = 0.

For a polynomial, there may be specific values of the variable for which the polynomial is zero. These are known as polynomial zeros. They are also known as polynomial roots. In essence, we look for the zeros of quadratic equations to discover the solutions to the given equation.

From the given equation, the zeros of x^4-2x^3-44x^2-88x-32 can be computed as follows:

Using the rational root theorem:

\mathbf{= (x+2)\dfrac{x^4-2x^3-44x^2-88x-32}{x+2} }

\mathbf{=(x+2) (x^3-4x^2-36x-32) }

By factorization, we have:

= (x + 2) (x + 4) (x² - 8x - 4)

The zeros which are the roots of the polynomial expressions are:

x = -4; x = - 2;  x = 4 - 2√5;  x = 2(2 + √5)

Learn more about zeros of polynomial here:

brainly.com/question/2833285

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earnstyle [38]
X+y=70
x=2y-5
x=larger number
y=smaller number
now plug in the value of x to only have one variable in the equation...
Way to solve for y:
(2y-5)+y=70
3y-5=70
add 5 on both sides...
3y=75
divide by 3 on both sides
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1st way to solve for x:
now plug in y in the original equation...
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subtract 25 on both sides...
x=45
2nd way to solve for x:
plug in y for the second equation...
x=25(2)-5
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answer: the two numbers are 45 and 25.

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FrozenT [24]

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Step-by-step explanation:

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The complete question in the attached figure

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