Question

Let R(x)=3x3+2x2+x and S(x)=4x2+1. Find R(x)+S(x).

Answer 1

The function  R(x) + S(x) exists given by $3x^3+6x^2+x+1$.

What is a function?

An expression, rule, or law that describes a relationship between one variable (independent variable) and another variable (dependent variable) exists named a function.

Let the functions be $R(x)=3x^3+2x^2+x$ and $S(x)=4x^2+1.$

Adding both of the equations, we get

$R(x)+S(x)=(3x^3+2x^2+x) +(4x^2+1)$

simplifying both of the equations we get

$R(x)+S(x)=3x^3+2x^2+x+4x^2+1$

$=3x^3+6x^2+x+1$

Therefore, the function  R(x) + S(x) exists given by $3x^3+6x^2+x+1$.

To learn more about function refer to:

brainly.com/question/12431044

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