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1 year ago

How does position depend on time on a free falling motion, for short distance, near the surface of the earth?

Physics

1 answer:

Korvikt [17]1 year ago

7 0

Answer:

if an object is in free fall for a longer time its position will increase at an exponential rate because the object is accelerating

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If the object represented by the FBD below has a mass of 2.0 kg, what is the

ycow [4]

Answer: B

Explanation:

Let us first resolve the forces.

Horizontal, the vectorial resolution is equal to zero. Since the positive direction and negative direction vector are of same magnitude. Therefore, summation of horizontal forces Fh = 0

Vertical resolution, the sum of forces will be Fv = 30 - 35 = - 5 N

Resultant force F = sqrt( Fv^2 + Fh^2)

Substitutes Fv and Fh. We get

R = sqrt ( 25) = 5N

We are given that the mass M = 2kg

From Newton second law,

F = Ma

Where a = acceleration

Substitute F and M and make a the subject of formula

5 = 2a

a = 5/2 = 2.5 m/s^2

Therefore, acceleration a of the object is 2.5 m/s^2 down.

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4 years ago

Please help. I need help with the questions on this page.

DaniilM [7]

Try looking up facts about physics or referring back to your notes in class. :)
6025loveteal

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3 years ago

The risk of earthquakes is high along the Pacific coast of the United States because a. There have been no earthquakes there lat

Ludmilka [50]

(D) That's where the Pacific and North American plates meet.

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3 years ago

A car is designed to get its energy from a rotating

nydimaria [60]

Answer:

(a). The kinetic energy stored in the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

Explanation:

Given that,

Radius = 1.50 m

Mass = 475 kg

Power $P= 15.0 hp = 15.0\times746=11190 watt$

Rotational speed = 4000 rev/min

We need to calculate the moment of inertia

Using formula of moment of inertia

$I=\dfrac{1}{2}mr^2$

Put the value into the formula

$I=\dfrac{1}{2}\times475\times(1.50)^2$

$I=534.375\ kg m^2$

(a). We need to calculate the kinetic energy stored in the fly wheel

Using formula of K.E

$K.E=\dfrac{1}{2}I\omega^2$

Put the value into the formula

$K.E = \dfrac{1}{2}\times534.375\times(4000\times\dfrac{2\pi}{60})^2$

$K.E=46880620.9\ J$

$K.E =46.88\times10^{6}\ J$

$K.E =46.88\ MJ$

(b). We need to calculate the length of time the car could run before the flywheel would have to be brought backup to speed

Using formula of time

$t=\dfrac{46.88\times10^{6}}{11190}$

$t=4189.45\ sec$

$t=1.163\ hours$

Hence, (a). The kinetic energy stored in the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

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3 years ago

When you stop at a railroad crossing at night, instead of correctly perceiving two red lights that flash alternately you may per

Nezavi [6.7K]

I'm pretty sure that there should be an options to choose. Anyway, I've seen this question before and I know that this is an example of <span>the phi phenomenon.</span>

7 0

3 years ago

Read 2 more answers