How does position depend on time on a free falling motion, for short distance, near the surface of the earth?
1 answer:
Answer:
if an object is in free fall for a longer time its position will increase at an exponential rate because the object is accelerating
You might be interested in
F = ma
a = f/m
if f doubled , acc. will be doubled
The reasoning for this is false
Answer: im not sire
Explanation: very sorry im not sure
Answer:
me no speak d english
Explanation:
Answer:
1.98s
Explanation:
The time taken to hit the ground is given by
h=ut+ 1/2 at^2
but u =0
so we have
h=1/2at^2
making t the subject
t=√2h/g
√2×19.6/10
1.98s
