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Natalka [10]
3 years ago
11

An airplane increases its speed from 100 m/s to 160 m/s, at the average rate of 15 m/s2. How much time does it take for the comp

lete increase in speed? 00577s O 40s O 0.25s O 17.3s
Physics
2 answers:
Vladimir [108]3 years ago
7 0

Answer: 4 s

Explanation: In order to solve this problem we have to use tge following kinematic expression:

vf=vo+a*t;  where vf and vo are the final and initial speed. a is the average acceleration and t,the time.

then we have:

t= (160-100) m/s/(15 m/s^2)= 4 s

Kipish [7]3 years ago
6 0

Answer:

4.0 s

Explanation:

Given data

Initial speed (V₀): 100 m/s

Final speed (vf): 160 m/s

Acceleration (a): 15 m/s²

Time (t): ?

In an uniformly accelerated motion, the acceleration is equal to the change in the speed divided by the time elapsed.

a = Δv/t

t = Δv/a = (vf - V₀)/a = (160 m/s - 100 m/s)/ (15m/s²) = 4.0 s

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Answer:

c

Explanation:

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The chemical substances in food that help maintain our body are known as what?
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Nutrients

Explanation:

4 0
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A +2e charge is at the point (-1,0) mm in the x,y plane. A –e charge is at the point (0,1) mm. What is the electric field at the
Gennadij [26K]

Answer:

Let I and j be the unit vector along x and y axis respectively.

Electric field at origin is given by

E= kq1/r1^2 i + kq2/r2^2j

= 9*10^9*1.6*10^-19*/10^-6*(2i+ j)

= (2.88i + 1.44j)*10^-3 N/C

Force on charge= qE= 3*10^-19*1.6*(2.88i +1. 44 j) *10^-3

F= (1.382 i + 0.691 j) *10^-21

 

 Goodluck

Explanation:

4 0
2 years ago
A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow- dryer is 11 Amps, and th
AURORKA [14]

Answer:

(a) 1320 W

(b) 480 W

(c) E':E ≈ 11:2

Explanation:

(a) Applying,

P' = VI'................. Equation 1

Where P' = Power of the blow-dryer, V = Voltage, I = current rating of the blow-dryer.

From the question,

Given: V = 120 V, I' = 11 A

Substitute these values into equation 1

P = (120×11)

P = 1320 W

(b) Similarly,

P = VI................... Equation 2

Where P = Power of the vacuum cleaner. I = current rating of the vacuum cleaner.

Also Given: I = 4 A,

Therefore

P = 4(120)

P = 480 W

(c)

E' = P'/t'............. Equation 3

E = P/t................ Equation 4

Where E' = Energy of the blow-dryer, t' = time of use of the blow-dryer, E = Energy of the vacuum cleaner, t = time of use of the vacuum cleaner

From the question,

Given: t' = 15 minutes = (15×60) = 900 seconds, t = 30 minutes = (30×60) = 1800 seconds

Substitute these values into equation 3 and 4

E' = 1320/900

E' = 1.47 J,

E = 480/1800

E = 0.267

Therefore,

E':E = 1.47:0.267

E':E ≈ 11:2

5 0
3 years ago
In a certain two slit diffraction experiment, two slits 0.02mm wide are spaced0.2mm between centers.(a) How many fringes appear
Kamila [148]

Answer:

a)   m = 10  and    b)  λ  = 3.119 10⁻⁷ m

Explanation:

In the diffraction experiments the maximums appear due to the interference phenomenon modulated by the envelope of the diffraction phenomenon, for which to find the number of lines within the maximum diffraction center we must relate the equations of the two phenomena.

Interference equation      d sin θ = m λ

Diffraction equation         a sin θ = n λ

Where d is the width between slits (d = 0.2 mm), a is the width of each slit (a = 0.02 mm). θ is the angle, λ the wavelength, m and n  are an integer.

Let's find the relationship of these two equations

    d sin θ / a sin θ = m Lam / n Lam

The first maximum diffraction (envelope) occurs for n = 1, let's simplify

    d / a = m

Let's calculate

    m = 0.2 / 0.02

    m = 10

This means that 10 interference lines appear within the first maximum diffraction.

b) let's use the interference equation, remember that the angles must be given in radians

    θ = 0.17 ° (π rad / 180 °) = 2.97 10⁻³ rad

    d sin  θ = m λ

    λ = d sin θ / m

    λ = 0.2 10⁻³ sin (2.97 10⁻³) / 2

    λ  = 3.119 10⁻⁷ m

8 0
3 years ago
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