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Natalka [10]
2 years ago
11

An airplane increases its speed from 100 m/s to 160 m/s, at the average rate of 15 m/s2. How much time does it take for the comp

lete increase in speed? 00577s O 40s O 0.25s O 17.3s
Physics
2 answers:
Vladimir [108]2 years ago
7 0

Answer: 4 s

Explanation: In order to solve this problem we have to use tge following kinematic expression:

vf=vo+a*t;  where vf and vo are the final and initial speed. a is the average acceleration and t,the time.

then we have:

t= (160-100) m/s/(15 m/s^2)= 4 s

Kipish [7]2 years ago
6 0

Answer:

4.0 s

Explanation:

Given data

Initial speed (V₀): 100 m/s

Final speed (vf): 160 m/s

Acceleration (a): 15 m/s²

Time (t): ?

In an uniformly accelerated motion, the acceleration is equal to the change in the speed divided by the time elapsed.

a = Δv/t

t = Δv/a = (vf - V₀)/a = (160 m/s - 100 m/s)/ (15m/s²) = 4.0 s

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You toss a conductive open ring of diameter d = 1.75 cm up in the air. The ring is flipping around a horizontal axis at a rate o
Mama L [17]

Answer:

The maximum emf induced in the ring

= (2.882 × 10⁻⁷) V

Explanation:

According to the law of electromagnetic induction, the emf induced in the ring is given by

E = N BA w sin wt

The maximum emf induced is

E = N BA w

B = 30.5 μT = (30.5 × 10⁻⁶) T

A = (πD²/4)

D = 1.75 cm = 0.0175 m

A = (π×0.0175²/4) = 0.000240625 m²

Nw = 2π × 6.25 = 39.29 rad/s

E = 30.5 × 10⁻⁶ × 0.000240625 × 39.29

E = (2.882 × 10⁻⁷) V

Hope this Helps!!!

8 0
3 years ago
Difference between static and kinetic friction in physics
KIM [24]
The force of static friction keeps a stationary object at rest. Once the force of static friction is overcome, the force of kinetic friction is what slows down a moving object.
4 0
3 years ago
Friction _____.
quester [9]

Answer:

all above

Explanation:

friction is necessary to live

8 0
2 years ago
What is the mass of an object moving with 80N of force and an acceleration of 8 m/s2?
OverLord2011 [107]

Answer:

10 Kg

Explanation:

Force is equal to mass times acceleration

therefore mass is equal to force divided by acceleration

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6 0
2 years ago
A discus thrower turns with angular acceleration of 50 rad/s2, moving the discus in a circle of radius 0.80m. Find the radial an
anyanavicka [17]

Answer:

The value of tangential acceleration \alpha_{t} =  40 \frac{m}{s^{2} }

The value of radial acceleration \alpha_{r} = 80 \frac{m}{s^{2} }

Explanation:

Angular acceleration = 50 \frac{rad}{s^{2} }

Radius of the disk = 0.8 m

Angular velocity = 10 \frac{rad}{s}

We know that tangential acceleration is given by the formula \alpha_{t} = r \alpha

Where r =  radius of the disk

\alpha = angular acceleration

⇒ \alpha_{t} = 0.8 × 50

⇒ \alpha_{t} = 40 \frac{m}{s^{2} }

This is the value of tangential acceleration.

Radial acceleration is given by

\alpha_{r} = \frac{V^{2} }{r}

Where V = velocity of the disk = r \omega

⇒ V = 0.8 × 10

⇒ V = 8 \frac{m}{s}

Radial acceleration

\alpha_{r} = \frac{8^{2} }{0.8}

\alpha_{r} = 80 \frac{m}{s^{2} }

This is the value of radial acceleration.

7 0
3 years ago
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