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9 months ago

14

suppose that in a random selection of 100 colored candies, 21% of them are blue. the candy company claims that the percentage

of blue candies is equal to 30%. use a 0.10 significance level to test that claim.

1 answer:

Nadya [2.5K]9 months ago

5 0

<u>The z = - 1.963 </u><u>lies </u><u>between -1.645 and 1.645 we fail to reject the </u><u>null hypothesis</u><u>.</u>

What does null hypothesis mean?

The null hypothesis is a typical statistical theory which suggests that no statistical relationship and significance exists in a set of given single observed variable, between two sets of observed data and measured phenomena.

Alternative hypothesis: p not equal to 0.30

$z =\frac{ 0.21 - 0.30}{\sqrt{0.30 ( 1- 0.30)/100} }$

$z = \frac{0.09}{0.04582575694}$

z = - 1.963

Critical value at α = 0.10 is 1.645

Therefore, z=-0.89 lies between -1.645 and 1.645 we fail to reject the null hypothesis.

Learn more about Null hypothesis

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Step-by-step explanation:

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2 years ago

The rule for the number of fish in a home aquarium is 1 gallon of water for each inch of fish length. Marta's aquarium holds 22

Anuta_ua [19.1K]

Answer:

Fish A is 4 inches.

Fish B is 5 inches.

Step-by-step explanation:

22=3a+2b

and

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So,

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3 years ago

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

4 0

3 years ago

PLS HELP ASAP!!!!!

zmey [24]

B. (7,-2) is the answer

6 0

2 years ago

shepuryov [24]

$\frac{a^{12}b^{8}}{a^{2}b^{4}}$

remember
(ab)/(cd)=a/c times b/d

also $\frac{x^{m}}{x^{n}}= x^{m-n}$

split it up with like terms

$\frac{a^{12}}{a^{2}}$ times $\frac{b^{8}}{b^{4}}$

do subtraction
for a's
12-2=10

b's
8-4=4

answe is $a^{10}b^{4}$

first one

5 0

3 years ago

Read 2 more answers