Explanation:
Quite a number of properties varies across a period. Some remains constant whereas others decreases.
As one moves from left to right;
- The energy level remains the same.
- The ionization energy increases progressively as a result of increasing nuclear charge.
- Electron affinity increases from left to right.
- Electronegativity increases.
- Electropositivity decreases.
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Answer:
30 feet /second
Explanation:
60 feet/ 2 sec = 30 feet/sec
Answer:
The answer is B - At dynamic equilibrium, the reactions continue but the amounts of reactants and products do not change.
Explanation:
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Answer:
The pH is 8,45 and it is basic.
Explanation:
The pH is a measure that gives us an idea of the acidity or alkalinity of a solution. It is calculated as:
pH = -log (H +)= -log (0.0000000035)=8, 46
The pH scale ranges from values of 0 to 14 (less than 7.0 is acidic and greater than 7.0 is basic, a pH = 7.0 is neutral).
In this case, the solution is basic (value greater than 7.0 ).
Answer:
9.82% of iron (II) will be sequestered by cyanide
Explanation:
We should first consider that Iron (II) and cyanide react to form the following structure:
[Fe(CN)₆]⁻⁴
Having considered this:
5.60 Lt Fe(II) 3.00x10⁻⁵ M ,this is, we have 5.60x3x10⁻⁵ = 1.68x10⁻⁴ moles of Fe⁺² (in 5.60 Lt)
Then , we have 9 ml NaCN 11.0 mM:
9 ml = 0.009 Lt
11.0 mM (milimolar) = 0.011 M (mol/lt)
So: 0.009x0.011 = 9.9x10⁻⁵ moles of CN⁻ ingested
As we now that the complex structure is formed by 1 Fe⁺² : 6 CN⁻ :
9.9x10⁻⁵ moles of CN⁻ will use 1.65x10⁻⁵ moles of Fe⁺² (this is, this amount of iron (II) will be sequestered
[(1.65x10⁻⁵ sequestred Fe⁺²)/(1.68x10⁻⁴ total available Fe⁺²)x100
% sequestered iron (II) = 9.82%