How/what do I answer this?--> "heat of the chemical reactions" like this is the question :/
1 answer:
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<u>Answer:</u> The heat required will be 58.604 kJ.
<u>Explanation: </u>
To calculate the amount of heat required, we use the formula:
Q= heat gained or absorbed = ? J
m = mass of the substance = 100 g
c = heat capacity of water = 4.186 J/g ° C
Putting values in above equation, we get:
Q = 58604 Joules = 58.604 kJ (Conversion factor: 1 kJ = 1000J)
Thus, heat released by 100 grams of ice is 58.604kJ.
Answer : -19.6
Explanation : We can calculate this using the combine equation of boiling point and depression in freezing point and obtain a combined equation which is
∆T(f) = ∆T(b) x {K(f) / K(b)} ;
Where ∆T(f) is depression in freezing point,
∆T(b) is elevation in boiling point,
K(f) is cryoscopic constant for water it is 1.86
K(b) is ebullioscopic constant for water it is 0.512
So we can solve the equation,
∆T(f) = (105.4 -100) X = 19.6
So when we have the freezing point depression as 19.6,
we know water freezes at 0° C so the freezing point will be 0 - 19.6 = -19.6 °C