Question

Consider the reaction:

Answer 1

Equilibrium constant for the reaction CaCl₂.2H₂O (s) <-------> CaCl₂ (s) + H₂O (g) is [H₂O]².

Equilibrium constant is a temperature dependent constant which does not depend on the concentration of reactant or product.

The reaction given is:

CaCl₂.2H₂O (s) <-------> CaCl₂ (s) + H₂O (g)

The equilibrium constant for the given reaction is given by:

Keq = [H₂O]² [CaCl₂] / [CaCl₂.2H₂O]

Since, we know that the concentration of a solid remain unity.

Hence, [CaCl₂] = 1

[CaCl₂.2H₂O] = 1

So, the equilibrium constant becomes,

Keq = [H₂O]²

Hence, Equilibrium constant for the reaction CaCl₂.2H₂O (s) <-------> CaCl₂ (s) + H₂O (g) is [H₂O]²

Learn more about Equilibrium constant here, brainly.com/question/10038290

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