The acid-dissociation constants of sulfurous acid (H2SO3) are ka1 = 1. 7 × 10^-2 and at 25. 0 °C. Calculate the ph of a 0. 163 m

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2 years ago

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aqueous solution of sulfurous acid.

1 answer:

Cloud [144] · Answer 1 · 2023-12-25T17:18:41+03:00

The pH of a 0.163 m aqueous solution of sulfurous acid is 1.28

<h3>What is an Aqueous Solution?</h3>

Aqueous solution is defined as the type of solution which has a high solubility in water.

To obtain the ph of a 0.163 m aqueous solution of sulfurous acid, we would have to:

First construct the ICE table:

Next, we would have to express the acid dissociation of sulfurous acid:

$K_{a} = \frac{[H^{+} ][HSO_{3} ^{-} ]}{{H_{2} SO_{3} }}$

By putting the values in equation :

{x²}{(0.163 - x)} = 1.7 x 10⁻²

{x²}{0.163} = 1.7 x 10⁻²

x = 0.052640 M

pH = 1.28.

Thus the pH of a 0.163 M aqueous solution of sulfurous acid is 1.28.

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