Determine the net number of sigma bonds, the net number of pi bonds, and the overall bond order for N2+. Use 0.5 to indicate a f
ractional bond order.
1 answer:
Answer:
Net number of sigma bonds = 1
Net number of pi bonds = 2
Overall bond order = 3
Explanation:
Electronic configuration of N2 ia
1s2 2s2 2p3
There is head to head overlap in pz orbital. Thus, there is one sigma bond
Pi bond is formed whenever there is side wise overlapping. Since both px and py undergoes overlapping to form pi bond, there are two pi bonds
Bond order = 0.5 (bonding electron – antibonding electron)
= 0.5 (8-2) = 0.5*6 = 3
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