Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer:
Srry Cant read it :(
Step-by-step explanation:
Answer:
13.9%
Step-by-step explanation:
The value of car is modeled as:
Here we can see that, each year Nathan has considered 0.861 of the previous year value or we can say that Nathan has considered 86.1% of the previous year value. So,
We subtract the percentage value considered from 100 to find out the percentage decrease in the value of the car.
The value of new car is decreasing by 13.9% each year.
Answer:
c is not a fuction
Step-by-step explanation:
1kg is 1000 grams. If each orange is 100g, 10 oranges is 1000g or 1kg. The answer is B or 10 oranges.
