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Sunny_sXe [5.5K]
1 year ago
14

How much work needs to be done to launch a baseball (145 g) at a speed of 108 MPH? The unit is Joule.

Physics
2 answers:
nalin [4]1 year ago
8 0

The work done in launching the baseball is 169 J.

<h3>What is work-energy theorem ?</h3>

The work-energy theorem states that, the net work done on a system is equal to the change in kinetic energy of the system.

Here,

Mass of the baseball, m = 145g

Speed of the baseball, v = 108 Mph = 48.28 m/s

According to work-energy theorem,

Work done, W = Kinetic energy

W = 1/2 mv²

W = 1/2 x 145 x 10⁻³ x 48.28²

W = 169 J

Hence,

The work done in launching the baseball is 169 J.

To learn more about work-energy theorem, click:

brainly.com/question/30759174

#SPJ2

sergiy2304 [10]1 year ago
6 0

Answer:

Given

m=145g=0.145kg (cause mass has unit kg)

v=108mph=48.28m/s

Find the work need

W=K (Work-Energy theorem)

K=1/2•m•v²

K=1/2•0.145•48.28²

K=168.99J

So, W=K=168.99J

Please give Brainliest

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2 years ago
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Please help with questions 32-35, especially 34
DENIUS [597]
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P = 230 * 4 = 920 w

In short, Your Answer would be: 920 w

33. I = P/V

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In short, Your Answer would be: 4 Ampere

34. Now, for this part you've given Voltage & Power, and you need to calculate Current & Resistance, so you could apply two equations here:

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