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Alika [10]
3 years ago
8

If the density of an object is less than the density of water, what will the object do?

Physics
1 answer:
ValentinkaMS [17]3 years ago
4 0
C float bc it is lesser or lighter than water
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The Geocentric Model was what scientists
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Galileo Galilei was looking into a telescope and he realized we orbit around the sun and the moon orbits around us

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4. Calculate the kinetic energy of a 4.7 kg object moving at a speed of 7 m/s. SHOW YOUR WORK
SashulF [63]

Answer:

\boxed {\boxed {\sf 115.15 \ J}}

Explanation:

Kinetic energy is the energy an object possesses due to motion. It is calculated with the following formula.

E_K= \frac{1}{2} mv^2

The mass of the object is 4.7 kilograms. The velocity of the object is 7 meters per second.

  • m= 4.7 kg
  • v= 7 m/s

Substitute the values into the formula.

E_K= \frac{1}{2} (4.7 \ kg)(7 \ m/s)^2

Solve the exponent.

  • (7 m/s)²= 7 m/s * 7 m/s = 49 m²/s²

E_K= \frac{1}{2} (4.7 \ kg)(49 \ m^2/s^2)

Multiply the numbers together.

E_K = 2.35 \ kg * 49 \ m^2/s^2

E_K= 115.15 \ kg*m^2/s^2

Convert the units. 1 kilogram square meter per square second is equal to 1 Joule.

E_K= 115.15 \ J

The object has <u>115.15 Joules</u> of kinetic energy.

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A 16.0 kg crate rests on a shelf 1.80 m above the floor in a warehouse. A forklift is used to raise the crate to a shelf 3.30 m
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A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).

<h3>What is potential energy?</h3>

It is the energy due to the position.

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U₁ = m × g × h₁ = 16.0 kg × (9.81 m/s²) × 1.80 m = 283 J

A forklift is used to raise the crate to a shelf 3.30 m (h₂) above the warehouse floor. The potential energy is:

U₂ = m × g × h₂ = 16.0 kg × (9.81 m/s²) × 3.30 m = 518 J

The increase in the potential energy is:

518 J - 283 J = 235 J ≈ 240 J

A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).

Learn more about potential energy here: brainly.com/question/23979653

#SPJ1

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The cylinder of gravity of cylinder is where
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In uniform gravity it is the same as the centre of mass. For regular shaped bodies it lies at the centre of the that particular body. Hence for a cylinder centre of gravity lies at the midpoint of the axis of the cylinder.

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