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dedylja [7]
11 months ago
11

The effusion rate of H2 molecules is 4.342 times that of an unknown gas. Determine the molar mass of the unknown gas.

Chemistry
1 answer:
Grace [21]11 months ago
8 0

The effusion rate of H2 molecules is 4.342 times that of an unknown gas. Determine the molar mass of the unknown gas. You can write the formula for Graham's law of diffusion or effusion of gases as: rate 1 / rate 2 = √ (mass 2 / mass 1) , where: rate 1 and rate 2 - Rates of effusion or diffusion of Gas 1 and 2, respectively, measured moles per unit time

<h3>What is H2 molecules?</h3>

The chemical element hydrogen is represented by the letter H and atomic number 1. The lightest element is hydrogen. Under normal circumstances, hydrogen is a gas made up of diatomic molecules with the formula H2. It is non-toxic, tasteless, colorless, odorless, and extremely flammable. In the cosmos, hydrogen is the most prevalent chemical, making up around 75% of all ordinary matter. [note 1] Plasma hydrogen makes up the majority of stars like the Sun. On Earth, hydrogen mostly takes the form of molecules like water and organic substances. Each atom of hydrogen's most prevalent isotope, 1H, has one proton, one electron, and no neutrons.

To learn more about H2 molecules from the given link:

brainly.com/question/23274128

#SPJ4

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Answer:

Covalent bonds

Explanation:

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3 years ago
At 2°C, the vapor pressure of pure water is 23.76 mmHg and that of a certain seawater sample is 23.09 mmHg. Assuming that seawat
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Answer:

0.808  M

Explanation:

Using Raoult's Law

\frac{P_s}{Pi}= x_i

where:

P_s = vapor pressure of sea water( solution) = 23.09 mmHg

P_i = vapor pressure of pure water (solute) = 23.76 mmHg

x_i = mole fraction of water

∴

\frac{23.09}{23.76}= x_i

x_i = 0.9718

x_i+x_2=1

x_2 = 1- x_i

x_2 = 1- 0.9718

x_2 = 0.0282

x_i = \frac{n_i}{n_i+n_2}  ------ equation (1)

x_2 = \frac{n_2}{n_i+n_2}  ------ equation (2)

where; (n_2) = number of moles of sea water

(n_i) = number of moles of pure water

equating above equation 1 and 2; we have :

\frac{n_2}{n_i}= \frac{0.0282}{0.9178}

= 0.02901

NOW, Molarity =  \frac{moles of sea water}{mass of pure water }*1000

= \frac{0.02901}{18}*1000

= 0.001616*1000

= 1.616 M

As we assume that the sea water contains only NaCl, if NaCl dissociates to Na⁺ and Cl⁻; we have \frac{1.616}{2} =0.808 M

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1. Which elements are known as d-block elements?
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If it loses 2 electrons, the net charge on the atom will be 2+

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If the atom has 9 protons and 9 electrons, the net charge is +9 + (-9) = 0. The +9 is the 9 protons and the -9 is from the 9 electrons.

If two electrons are taken away, there would be 9-2 or 7 electrons with 9 protons. The net charge would then be +9 + (-7) = +2. +9 comes from the 9 electrons and -7 is from the 7 electrons.

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