Answer:
L=0.85M
Explanation:
ca3 (po4)
66gX1mol/310.18g=2.2178mol/2.5
Explanation:
The given data is as follows.
Diameter = 0.1 m, = 1000 kPa
= 500 kPa
Change in pressure = 1000 kPa - 500 kPa = 500 kPa
Since, 1000 Pa = 1 kPa. So, 500 kPa will be equal to .
Q = 5 = = 0.0833
It is known that Q =
where, A = cross sectional area
V = speed of the fluid in that section
Hence, calculate V as follows.
V =
=
=
= 10.61 m/sec
Also it is known that Reynold's number is as follows.
Re =
=
= 1061032.954
As, it is given that the flow is turbulent so we cannot use the Hagen-Poiseuille equation as follows. Therefore, by using Blasius equation for turbulent flow as follows.
L =
= 90.328 m
Thus, we can conclude that 90.328 m length galvanized iron line should be used to reach the desired outlet pressure.
The volume that a 0.323-mol sample of a gas will occupy at 265 K and a pressure of 0.900 atm is 7.81L.
<h3>HOW TO CALCULATE VOLUME?</h3>
The volume of a gas can be calculated using the following formula:
PV = nRT
Where;
- P = pressure (atm)
- V = volume (L)
- R = gas law constant (0.0821 Latm/molK)
- n = number of moles
- T = temperature (K)
V = 0.323 × 0.0821 × 265 ÷ 0.900
V = 7.027 ÷ 0.9
V = 7.81L
Therefore, the volume that a 0.323-mol sample of a gas will occupy at 265 K and a pressure of 0.900 atm is 7.81L.
Learn more about volume at: brainly.com/question/1578538
There aren't any options given but I would say the answer is "continuous spectrum"