Answer is Sodium Hydroxide.
Answer:
0.7457 g is the mass of the helium gas.
Explanation:
Given:
Pressure = 3.04 atm
Temperature = 25.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (25.0 + 273.15) K = 298.15 K
Volume = 1.50 L
Using ideal gas equation as:

where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
3.04 atm × 1.50 L = n × 0.0821 L.atm/K.mol × 298.15 K
<u>⇒n = 0.1863 moles</u>
Molar mass of helium = 4.0026 g/mol
The formula for the calculation of moles is shown below:
Thus,

<u>0.7457 g is the mass of the helium gas. </u>
It is 50. This is because heat goes from higher temperatures to lower and nothing else in the options is lower.
Answer:
<em>C.Activation energy is the same in the forward and reverse direction.</em>
<em>Explanation:</em>
<em>All these are true statements expect for option "C"</em>
Answer:
The correct answer is option E.
Explanation:

Mass of ferric oxide decomposed = 57.0 g
Moles of ferric oxide decomposed = 
According to reaction, 2 moles ferric oxide on combustion gives 824.2 kJ of heat.
Then heat given by on decomposition of 0.35625 mol of ferric oxide will be:

So, on decomposition of 57.0 grams of ferric oxide 147 kilo Joules of heat was released.