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IrinaVladis [17]
2 years ago
6

a chemist makes of silver perchlorate working solution by adding distilled water to of a stock solution of silver perchlorate in

water. calculate the concentration of the chemist's working solution. round your answer to significant digits.
Chemistry
1 answer:
Elodia [21]2 years ago
7 0

The concentration of the chemist's working solution is 6.718 mol/L.

Given,

The volume of silver perchlorate solution (V₁) = 790 ml.

The volume of distilled water added to the silver perchlorate(V₂) = 290ml.

The concentration of a stock solution of silver perchlorate (C₂) = 18.3 mol/L.

We have to find the concentration of the chemist's working solution (C₁).

As we know,

V₁C₁ = V₂C₂

From the above formula, we get,

C₁ = V₂C₂/V₁

C₁ = 290 × 18.3/ 790

C₁ = 6.718 mol/L

The concentration of the working solution = 6.718 mol/L

Hence, the concentration of the chemist's working solution is 6.718 mol/L.

To learn more about the concentration or stock's solution, visit: brainly.com/question/14510306

#SPJ4

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Select all that apply.
julia-pushkina [17]
Answer is:increase [Cl₂] and remove HCl from the product.
Chemical reaction: Cl₂ + CH₂Cl₂ → CHCl₃(chloroform) + HCl.
According to Le Chatelier's Principle, the position of equilibrium moves to counteract the change, the position of equilibrium will move so that the concentration of reactants decrease (Cl₂) and concentration of products of chemical reaction increase (CHCl₃) if increase concentration of reactants and decrease concentration of products.

 


7 0
4 years ago
An atom of an element has 54 protons. Some of the elements atoms have 77 neutrons, while other atoms have 79 neutrons. What are
Alja [10]

Answer:

The atomic numbers of both are 54 while the mass numbers are 131 and 133 respectively.

Explanation:

- The number of protons = Atomic number. So, if the atom has 54 protons and it remained unchanged, then the two types of atoms of this element both have atomic numbers of 54.

- On the other hand, mass number is the sum of protons and neutrons

So, if type 1 has protons = 54 and neutrons = 77: mass number = 54 + 77 = 131

if Type 2 has protons = 54 and neutrons = 79: mass number = 54 + 77 = 133

(Since the possibility of atoms of the same element to have different mass numbers but the same atomic number is called isotopy). The two types of atoms with mass numbers 131 and 133 described are isotopes.

7 0
3 years ago
If the balloon had a volume of 3 L at a depth of 50 m, what was the original volume of the balloon it we assume the pressure at
disa [49]

If the balloon had a volume of 3 L at a depth of 50 m, the original volume of the balloon will be

<h3 /><h3>What is Significant figures ?</h3>

Significant figures are the number of digits in a value, often a measurement, that contribute to the degree of accuracy of the value.

The pressure at a depth of 40 m is the hydrostatic pressure of the water plus the atmospheric pressure.

The hydrostatic pressure P of a liquid is given by the formula ;

P = ρgh

where,

  • ρ = the density of the liquid (Density of water = 1000 kg m⁻³)
  • g = the acceleration due to gravity (9.81 ms⁻²)
  • h = the depth of the liquid (Given : 50 m)

P =  1000 kg m⁻³ x 9.81 ms⁻² x 50 m

   = 1000 kg m⁻¹ x 9.81 s⁻² x 50

   = 4.9 x 10⁵ Pa

Lets's Convert Pa in to atm

    =   4.9 x 10⁵ Pa x 1 / 103. 325 x 10³ Pa

    = 4.7 atm

Mow, lets calculate P(atm) ;

P(atm) = 14.7 psi x 1 atm / 14.7 psi

          = 1 atm

Total Pressure at 50 m is ;

P(total) = 4.7 atm + 1 atm

            = 5.7 atm

Now we can apply Boyle's Law to calculate the volume of the balloon at the surface.

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

According to the question ;

  • P₁ = 5.7 atm  
  • P₂ = 1 atm
  • V₁ = 3 L
  • V₂ = ?

V₂ = 3 L x 5.7 atm  / 1 atm

     = 17.1 L

     = 20 L ( 1 significant figure)

Learn more about Boyles law here ;

brainly.com/question/1437490

#SPJ1

8 0
2 years ago
Write down the simple electron configurations of
vitfil [10]
B is the correct answer
5 0
3 years ago
Read 2 more answers
Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq) , as described b
Nostrana [21]

Answer:

0.676 grams of manganese (IV) oxide should be added.

Explanation:

Moles of chlorine gas = n

Volume of the chlorine gas = V = 205 mL = 0.205 L

Pressure of the chlorine gas = 705 Torr = \frac{705}{760}atm=0.928 atm

1 atm = 760 Torr

Temperature of the chlorine gas = T = 25°C = 25 + 273 K = 298 K

PV=nRT ( ideal gs equation)

n=\frac{PV}{RT}=\frac{0.928 atm\times 0.205 L}{0.0821 atm L/mol K\times 298 K}=0.00777 mol

MnO_2(s)+4HCl(aq)\rightarrow MnCl_2(aq)+2H_2O(l)+Cl_2(g)

According to reaction, 1 mole of chlorine gas is obtained from  1 mole of manganese(IV) oxide,then 0.00777 moles of chlorine gas will be obtained from :

\frac{1}{1}\times 0.00777 mol=0.00777 mol of manganese (IV) oxide

Mass of 0.00777 moles of manganese (IV) oxide:

0.00777 mol × 87 g/mol = 0.676 g

0.676 grams of manganese (IV) oxide should be added.

3 0
3 years ago
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