The given question is incomplete. The complete question is as follows.
A solution contains an unknown mass of dissolved barium ions. When sodium sulfate is added to the solution, a white precipitate forms. The precipitate is filtered and dried and then found to have a mass of 212 mg. What mass of barium was in the original solution? (Assume that all of the barium was precipitated out of solution by the reaction.)
Explanation:
When 
and 
are added then white precipitate forms. And, reaction equation for this is as follows.
It is given that mass (m) is 212 mg or 0.212 g (as 1 g = 1000 mg). Molecular weight of 
is 233.43.
Now, we will calculate the number of moles as follows.
No. of moles = mass × M.W
= 
= 0.00091 mol of
Hence, it means that 0.00091 mol of . Now, we will calculate the mass as follows.
Mass = moles × MW
= 
= 0.124 grams or 124 mg of barium
Thus, we can conclude that mass of barium into the original solution is 124 mg.
<h2><u>Answer</u> : - </h2>
Polywool fibre is <u>synthetic</u>.
⇒b. Synthetic
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Compounds
Explanation:
Compounds are substances that can be broken down by chemical means. They are categorized as pure substances due to their definite composition.
- Compounds are substances composed of two or more kinds of atoms or elements joined together in a definite grouping.
- Properties of compounds differs from those of the constituent atoms.
- Compounds are broken down by chemical means because they are products of chemical changes.
- Several kinds of compounds exists through combinations of atoms.
- Compounds have definite compositions
Learn more:
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Answer:
chemical-Acid rain eating away at the rock
Physical-Dust particles eroding the rock overtime in the wind
Explanation:
The H2 produced in a chemical reaction is collected through water in a eudiometer. The pressure (kPa) of the H2 gas is 98.89 kPa
The total pressure in a chemical reaction is the total sum of the partial pressure and the vapor pressure of the chemical substances taking place in the chemical reaction.
- Total pressure = partial pressure of H₂ gas + vapor pressure of H₂O
∴
The vapor pressure of H₂ gas = Total pressure in the eudiometer - partial pressure of H₂O
Given that:
- The total pressure in the eudiometer = 101.3 kPa
- The partial pressure of H₂O = 2.41 kPa
The vapor pressure of H₂ gas = 101.3 kPa - 2.41 kPa
The vapor pressure of H₂ gas = (101.3 - 2.41) kPa
The vapor pressure of H₂ = 98.89 kPa
Therefore, we can conclude that the vapor pressure of H₂ is 98.89 kPa.
Learn more about partial pressure here:
brainly.com/question/14281129?referrer=searchResults
