Two thousand dollars is invested at 5.5 percent interest compounded
quarterly for 2 years. Then the amount is $ 2230.88
<u>Solution:</u>
Given that Two thousand dollars is invested at 5.5 percent interest compounded  quarterly for 2 years
<em><u>The formula for amount using compounded quarterly is given as</u></em>:

Where, "p" is the principal sum
"R" is the rate of interest
"T" is the number of years
Here in this problem,
P = 2000 ; R = 5.5 ; T = 2 years
Plugging in values in formula we get,


On solving we get,

Hence the amount is $ 2230.88
 
        
             
        
        
        
Answer:
Yes it is!
Step-by-step explanation:
First do 8+7 which is 15, then subtract 1 to get 14
Hi! If this helped please make this the brainliest answer, I'm on a goal to get 5 brainest answers, thanks!
 
        
             
        
        
        
Answer:
X= 17
Step-by-step explanation:
In the picture above , you see that 
BAE =~ DAE 
So , just substitute the equation of each other and solve for x.
That's it.
 
        
                    
             
        
        
        
Answer:
if he wants to have $400000 on gis bank in 30 years at 4 %rate then he needs to deposit $15151.5 per month
 
        
             
        
        
        
Answer:
2L + 2W = 88
L = W + 12
L = 28 feet & W = 16 feet
Step-by-step explanation:
2L + 2W = 88
[] The perimeter of a rectangle is length + length + width + width, shortned as 2(legnth) + 2(width) and since the perimeter of the garden is 88, this option works.
L = W + 12
[] The length is 12 feet longer than the width, so the width + 12 will equal the length
Solving:
{ 2L + 2W = 88
{ L = W + 12
[Plug-in] 2(W + 12) + 2W = 88
[Distribute] 2W + 24 + 2W = 88
[Combine like terms] 4W + 24 = 88
[Subtract 24 from both sides] 4W = 64
[Divide both sides by 4] W = 16
L = W + 12 -> L = (16) + 12 -> L = 28
Have a nice day!<em> - Side note, is your screen okay? lol</em>
      I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather