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AlladinOne [14]
11 months ago
9

Solve for x. one fifth times the absolute value of the quantity x minus 4 end quantity minus 3 equals 6 A. x= -19 and x =-11 b.

x=-41 and x =49
c. x=-19 and x =11 d. x =-11 and x =19
Mathematics
1 answer:
Firdavs [7]11 months ago
6 0

The value of x in the given expression can be either -41 or 45. The correct option is B.

<h3>What is Absolute Value?</h3>

An absolute value of |x| {modulus of x} is the value of a real number x, the value we get is always a non-negative number, for example, |-5| will give 5, and also, |5| will give 5 as well.

Given the modulus function (1/5)|x - 4| - 3 = 6. Now, there will be two cases of this because the value of x can be either negative, x<0 or it can positive, x>0. Therefore, the given modulus function can be solved as shown below.

  • When x>0,

(1/5)(x-4) - 3 = 6

(x/5) - (4/5) - 3 = 6

(x - 4 - 15)/5 = 6

x - 4 -15 = 30

x = 30 + 15 + 4

x = 45

  • When x<0

(1/5)(-x+4) - 3 = 6

(-x/5) + (4/5) - 3 = 6

(- x + 4 - 15)/5 = 6

- x + 4 -15 = 30

-x = 30 + 15 - 4

-x = 41

x = -41

Hence, the value of x in the given expression can be either -41 or 45.

Learn more about Absolute value here:

brainly.com/question/1301718

#SPJ1

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