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Mrac [35]
1 year ago
9

A natural gas power plant is 60% efficient. if one cubic meter of natural gas provides 1000 btus of electricity. how many btus o

f waste heat were produced?
Chemistry
1 answer:
musickatia [10]1 year ago
3 0

400 BTU of wasted heat energy is present in the form of electricity.

<h3><u>Energy sources and usage</u></h3>
  • Potential energy sources include fossil fuels like coal, oil, and natural gas. Other energy sources include hydro, solar, and wind.
  • Additionally, nuclear energy may also come from radioactive materials.But energy will constantly lose its strength.
  • Industries would never be able to derive a full amount of energy from their sources.We can only obtain 60% of the energy in ideal situations, such as the Carnot engine. This is if the case is ideal. Actually, we receive considerably less than this for roughly 40%.

So, when efficiency is 60%, energy is used 60% of the time and lost 40% of the time. Thus, according to question, the energy that is wasted is:

1000 BTUx (40/100) = 400 BTU

To know more about energy sources and wastage, refer to:

brainly.com/question/8702962

#SPJ4

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Caffeine (C8H10N4O2) is a weak base with a pKb of 10.4. Calculate the pH of a solution containing a caffeine concentration of 41
RSB [31]

Answer:

pH → 7.47

Explanation:

Caffeine is a sort of amine, which is a weak base. Then, this pH should be higher than 7.

Caffeine + H₂O  ⇄  Caffeine⁺  +  OH⁻      Kb

1 mol of caffeine in water can give hydroxides and protonated caffeine.

We convert the concentration from mg/L to M

415 mg = 0.415 g

0.415 g / 194.19 g/mol = 2.14×10⁻³ mol

[Caffeine] = 2.14×10⁻³  M

Let's calculate pH. As we don't have Kb, we can obtain it from pKb.

- log Kb = pKb → 10^-pKb = Kb

10⁻¹⁰'⁴ = 3.98×10⁻¹¹

We go to equilibrium:

Caffeine + H₂O  ⇄  Caffeine⁺  +  OH⁻      Kb

Initially we have 2.14×10⁻³ moles of caffeine, so, after the equilibrium we may have (2.14×10⁻³ - x)

X will be the amount of protonated caffeine and OH⁻

     Caffeine     +    H₂O  ⇄  Caffeine⁺  +  OH⁻      Kb

   (2.14×10⁻³ - x)                         x                x

We make the expression for Kb:

3.98×10⁻¹¹ = x² / (2.14×10⁻³ - x)

We can missed the -x in denominator, because Kb it's a very small value.

So: 3.98×10⁻¹¹ = x² / 2.14×10⁻³

√(3.98×10⁻¹¹ . 2.14×10⁻³) = x → 2.92×10⁻⁷

That's the [OH⁻].  - log [OH⁻] = pOH

- log 2.92×10⁻⁷ = 6.53 → pOH

14 - pOH = pH → 14 - 6.53 = 7.47

4 0
3 years ago
The ro– group is the nucleophile. think about which group in the alkyl halide (iodoethane) is the leaving group. keep in mind th
jonny [76]
When Nucleophile (Alkoxide) reacts with Alkyl Halide (Substrate), Ether (product) is formed with the elimination of Leaving group (Iodide in this case).

This is SN² a nucleophilic substitution reaction which takes place in primary alkyl halides. Reaction is given as, 

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4 years ago
The study of organisms in relationship to their environment is .
laiz [17]

Answer:

Ecology.

Explanation:

Because you are epic.

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What is the volume of the liquid in the this diagram?<br>Would it be 37 mL or 36.5 mL?
vivado [14]

The volume of the liquid in this diagram shown above would be equal to 36.5 mL.

<h3>What is a graduated cylinder?</h3>

A graduated cylinder is also known as measuring cylinder and it can be defined as a narrow, cylindrical piece of laboratory equipment with marked lines, which are used to measure the volume of a liquid.

In order to take a reading for the measurement of the volume of a liquid such as water, you should ensure that your eye level is even with the center of the meniscus.

In this scenario, the volume of the liquid in this diagram would be 36.5 mL because each of the small lines on the graduated cylinder measures 0.5 mL.

Read more on graduated cylinder here: brainly.com/question/24869562

#SPJ1

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P + O2 → P4O10 balance the equation
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4P + 502 -> P4O10 this is the answer
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