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Anika [276]
3 years ago
15

What is the value of k for this aqueous reaction at 298 k?

Chemistry
1 answer:
TEA [102]3 years ago
5 0

Answer : The complete question is attached in answer.

The value of K will be = 2 X10^{-5}


Explanation : We can use the formula as;


∆G = -RT ln K


on rearranging we get, K = e^({-deltaG/RT})

Therefore, we get,

∆G/RT = (26.81 kJ/mol ) / (0.008314 kJ/mol-K) X (298K) = 10.82


So, K = e^{-10.82}

Therefore, K = 2 X 10^{-5}

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