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kirill115 [55]
3 years ago
12

a solution of iron 3 sulfate and a solution of lead 2 perchlorate react to produce lead 2 sulfate precipitate

Chemistry
1 answer:
777dan777 [17]3 years ago
7 0

Balanced equation :

Fe2(SO4)3 + 3Pb(ClO4)2 → 2Fe(ClO4)3 + 3PbSO4

<h3>Further explanation</h3>

Given

Word equation

Required

Balanced equation

Solution

Chemical equations can be expressed in terms of:

  • word equation
  • skeleton equation
  • balanced equation

Word equation :

a solution of iron 3 sulfate and a solution of lead 2 perchlorate react to produce lead 2 sulfate precipitate

Skeleton equation :

Fe2(SO4)3 + Pb(ClO4)2  → Fe(ClO4)3 + PbSO4

Balanced equation :

Fe2(SO4)3 + 3Pb(ClO4)2 → 2Fe(ClO4)3 + 3PbSO4

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Explanation:

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A 50.0 g sample of liquid water at 25.0 degree C is mixed with 29.0 g of water at 45 degree C. The final temperature of the wate
kotegsom [21]

<u>Answer:</u> The final temperature of water is 32.3°C

<u>Explanation:</u>

When two solutions are mixed, the amount of heat released by solution 1 (liquid water) will be equal to the amount of heat absorbed by solution 2 (liquid water)

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of solution 1 (liquid water) = 50.0 g

m_2 = mass of solution 2 (liquid water) = 29.0 g

T_{final} = final temperature = ?

T_1 = initial temperature of solution 1 = 25°C  = [273 + 25] = 298 K

T_2 = initial temperature of solution 2 = 45°C  = [273 + 45] = 318 K

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Putting values in equation 1, we get:

50.0\times 4.18\times (T_{final}-298)=-[29.0\times 4.18\times (T_{final}-318)]\\\\T_{final}=305.3K

Converting this into degree Celsius, we use the conversion factor:

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