Given vertex
![(h,k)](https://tex.z-dn.net/?f=%28h%2Ck%29)
the equation of the parabola is:
![f(x)=a(x-h)^2+k](https://tex.z-dn.net/?f=f%28x%29%3Da%28x-h%29%5E2%2Bk)
.
Our vertex is the point
![(3,5)](https://tex.z-dn.net/?f=%283%2C5%29)
so the equation is:
![f(x)=a(x-3)^2+5](https://tex.z-dn.net/?f=f%28x%29%3Da%28x-3%29%5E2%2B5)
. It remains to find a. We will use the point (1,-3) like
this:
Substitute x=1 and f(1)=-3 in the equation above we get the equation:
![-3=a(1-3)+5\\-3=-2a+5\\-2a=-8\\a=4](https://tex.z-dn.net/?f=-3%3Da%281-3%29%2B5%5C%5C-3%3D-2a%2B5%5C%5C-2a%3D-8%5C%5Ca%3D4)
Equation of the parabola then:
![f(x)=4(x-3)^2+5](https://tex.z-dn.net/?f=f%28x%29%3D4%28x-3%29%5E2%2B5)
.
Expand in order to get the general form:
Answer:
y (is less than or equal to) 3
Step-by-step explanation:
i hope this helps :)
<h3>
Answer: H. 33</h3>
=============================================
Work Shown:
Solve 5m^2 = 45 for m to get
5m^2 = 45
m^2 = 45/5
m^2 = 9
m = sqrt(9)
m = 3
I'm making m to be positive so that way the expression 12m is not negative. Otherwise, sqrt(12m) would not be a real number result.
--------------
Plug m = 3 into the expression we want to evaluate
m^3 + sqrt(12m)
3^3 + sqrt(12*3)
27 + sqrt(36)
27 + 6
33
Answer:
30%
for example for 100 the 30% of 100 is 30
but the 1/4 of 100 is 25
Step-by-step explanation:
MARK ME BRAINLIEST PLS I NEED IT
perimeter = 2L+2W
L=2+w
40 = 2L+2W
40= 2(2+w)+2W
40=4+2w+2w
36=4w
w=9
L=9+2=11
2(9) = 18, 2(11) = 22, 22+18 = 40
L=11
W=9
Area = L x w
area = 11x9= 99 square yards