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3 years ago

Juan graphed the solution to the inequality on the number line.

Mathematics

2 answers:

Serggg [28]3 years ago

7 0

The answer is the third one

den301095 [7]3 years ago

3 0

1.first false because it gives 8>8, that is false , but it is written 8=8
2.false because it gives 12>8 but written -12<8
3.gives 10>8, and it is written the same true
4.gives 4>8, but written 4<8

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How do you this question (pre-cal)

Novay_Z [31]

The goal to proving identities is to transform one side into the other. We can only pick one side to transform while the other side stays the same the entire time. The general rule of thumb is to transform the more complicated side (though there may be exceptions to this guideline).

So I'll take the left hand side and try to turn it into $\csc^2( B )$

One way we can do that is through the following steps:

$\frac{\tan(B) + \cot(B)}{\tan(B)} = \csc^2(B)\\\\\frac{\tan(B)}{\tan(B)} + \frac{\cot(B)}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\frac{1}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\cot(B) = \csc^2(B)\\\\1 + \cot^2(B) = \csc^2(B)\\\\1 + \frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)}{\sin^2(B)}+\frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)+cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{1}{\sin^2(B)} = \csc^2(B)\\\\\csc^2(B)=\csc^2(B) \ \ {\Large \checkmark}\\\\$

Since we've shown that the left hand side transforms into the right hand side, this verifies the equation is an identity.

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3 years ago

A back contains 120 marbles some are red and the rest are black They are 19 red marbles for every black marble How many red marb

egoroff_w [7]

Answer:

6.3 ?

Step-by-step explanation:

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Which inequality is true?

Andreas93 [3]

Answer:

2 awnser is the right on

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3 years ago

N(-2,-2) After a rotation 90 degrees counterclockwise

RUDIKE [14]

Answer: (2,-2)

Step-by-step explanation:

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2 years ago

How do you do this ? Please step by step explanation due tom

inna [77]

Answer: C im pretty sure

Step-by-step explanation:

Use this link it explains it pretty well

https://www.calculatorsoup.com/calculators/math/mixednumbers.php

Just copy and paste the link

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3 years ago