Answer:

<h3>
♁ Question : Solve for x</h3>
<h3>♁ Step - by - step explanation</h3>
Move 12x to L.H.S ( Left Hand Side ) and change it's sign
➛
Move 7 to R.H.S ( Right Hand Side) and change it's sign
➛
Subtract 12x from 15x
Remember that only coefficients of like terms can be added or subtracted.
➛
Add the numbers : 2 and 7
➛
Divide both sides by 3
➛ 
➛ 
The value of x is 
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☄ Now, let's check whether the value of x is 3 or not!
<h3>
☥ Verification :</h3>




L.H.S = R.H.S ( Hence , the value of x is 3 ).
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<h3>✒ Rules for solving an equation :</h3>
- If an equation contains fractions ,multiply each term by the L.C.M of denominators.
- Remove the brackets , if any.
- Collect the terms with the variable to the left hand side and constant terms to the right hand side by changing their sign ' + ' into ' - ' and ' - ' into ' + ' .
- Simplify and get the single term on each side.
- Divide each side by the coefficient of variable and then get the value of variable.
Hope I helped!
Have a wonderful time ! ツ
~TheAnimeGirl
Answer:
x>-2
Step-by-step explanation:
x-4x<5x+16
Subtract 5x from both sides:
x-4x-5x<16
Combine like terms:
-8x<16
Divide both sides by 8:
-x<2
Divide both sides by -1:
x>-2
Hope this helps!
911 is the key of power of mind
PEMDAS.
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
Lets apply that here.
72-[(3x2^3)+48]
So first we start with (3x2^3)
2^3=8
3*8=24
now we do 24+48 which equals 72
now we have 72-72 which equals zero.
So
72-[(3x2^3)+48] = 0
4x + 1 = x^2 + 3x - 1
4x = x^2 + 3x - 2
0 = x^2 -x - 2
0 = x^2 -x + 1 - 3
0 = (x - 1)^2 - 3
3 = (x - 1)^2
sqrt 3=(x-1) and (-(x-1))
x = 1+sqrt 3 and 1-sqrt 3
sqrt means square root