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Veronika [31]
3 years ago
14

Mr. Brown's class is collecting books for a book drive. They started with 2 books. On the first day, they had 6 books. On the se

cond day they had 18 books. Write an equation that models this situation.
A) y = 4x + 2
B) y = 2(3)x
C) y = 3x + 2
D) y = x2 + 2
Mathematics
2 answers:
IrinaVladis [17]3 years ago
5 0

we are given

Let's assume total number of books =y

number of days =x

They started with 2 books

so, first term is 2

second term is 6

third term is 18

we can see that this is geometric series

so, firstly we will find common ratio

r=\frac{6}{2}= 3

total number of terms is x+1

now, we can find nth term

y=2(r)^{x+1-1}

now, we can plug back r

we get

y=2(3)^{x}...........Answer

Aleonysh [2.5K]3 years ago
4 0
The answer is b

Aaaaa
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kiruha [24]

For this case we have the following expression:

\frac {216 ^ {n-2}} {(\frac {1} {36}) ^ {3n}} = 216

We multiply both sides by: (\frac {1} {36}) ^ {3n}

216 ^ {n-2} = 216 * (\frac {1} {36}) ^ {3n}

We divide both sides by 216:

\frac {216 ^ {n-2}} {216} = (\frac {1} {36}) ^ {3n}

To divide powers of the same base, we place the same base and subtract the exponents:

216 ^ {n-2-1} = (\frac {1} {36}) ^ {3n}\\216 ^ {n-3} = (\frac {1} {36}) ^ {3n}

Rewriting:

(6 ^ 3) ^ {n-3} = (\frac {1} {6 ^ 2}) ^ {3n}\\6 ^ {3n-9} = \frac {1} {6 ^ {6n}}\\6^{ 3n-9} * 6^{ 6n} = 1

To multiply powers of the same base, we place the same base and add the exponents:

6^{ 3n-9 + 6n} = 1\\6^{ 9n-9} = 1

We know that any number raised to zero is 1, a ^ 0 = 1.

So, for equality to be true:

9n-9 = 0\\9n = 9\\n = \frac {9} {9}\\n = 1

Answer:

n = 1

3 0
3 years ago
Read 2 more answers
I need the answer please
eduard

Answer:

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Step-by-step explanation:

v uh yhfnx zhjd dd djsi dh

Sorry i dont know but if you want points you could spam things like this and get points

8 0
2 years ago
How would I solve y-8+3(y+4)
konstantin123 [22]

Answer:

y-8+3y+12

4y+4

Step-by-step explanation:

y-8+3y+12

4y+4 is your answer

6 0
3 years ago
Look at picture <br>please help in less than 5 min
tiny-mole [99]
The answer is b
2^2*3*7=
4*3*7=
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7 0
3 years ago
Solve the problem. Use the Central Limit Theorem.The annual precipitation amounts in a certain mountain range are normally distr
bazaltina [42]

Answer:

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 109.0 inches, and a standard deviation of 12 inches.

This means that \mu = 109, \sigma = 12

Sample of 25.

This means that n = 25, s = \frac{12}{\sqrt{25}} = 2.4

What is the probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches?

This is the p-value of Z when X = 112. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{112 - 109}{2.4}

Z = 1.25

Z = 1.25 has a p-value of 0.8944.

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

7 0
3 years ago
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