All categories

2 years ago

Find the domain of the graphed function.

Mathematics

2 answers:

abruzzese [7]2 years ago

8 0

Answer:

Step-by-step explanation:

the graph stops at x=0, and continues to the right

OLga [1]2 years ago

6 0

Answer:

Step-by-step explanation:

Domain can be found by:

starting x-value < x < ending x-value (if thedot is opened)

starting x-value ≤ x ≤ ending x-value (if the dot is closed)

Our starting x-value is x = 0 by the graph.

For ending x-value, there is no ending x-value and thus:

0 ≤ x

x ≥ 0

You might be interested in

Hey get you points <br> hahahaha

Juli2301 [7.4K]

Thank youuuuuuuuuuuuuuuuuu

8 0

2 years ago

Read 2 more answers

6/15=3/x solve for x

denis23 [38]

Answer:15/2

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Someeee one?????????????????

Ad libitum [116K]

Answer:

Option B) $a_{n} = 2\cdot 4^{n-1}$

Step-by-step explanation:

The given geometric sequence is

2, 8, 32, 128,....

The general form of a geometric sequence is given by

$a_{n} = a_{1}\cdot r^{n-1}$

Where n is the nth term that we want to find out.

a₁ is the first term in the geometric sequence that is 2

r is the common ratio and can found by simply dividing any two consecutive numbers in the sequence,

$r=\frac{8}{2} = 4$

You can try other consecutive numbers too, you will get the same common ratio

$r=\frac{32}{8} = 4$

$r=\frac{128}{32} = 4$

So the common ratio is 4 in this case.

Substitute the value of a₁ and r into the above general equation

$a_{n} = 2\cdot 4^{n-1}$

This is the general form of the given geometric sequence.

Therefore, the correct option is B

Note: Don't multiply the first term and common ratio otherwise you wont get correct results.

Verification:

$a_{n} = 2\cdot 4^{n-1}$

Lets find out the 2nd term

Substitute n = 2

$a_{2} = 2\cdot 4^{2-1} = 2\cdot 4^{1} = 2\cdot 4 = 8$

Lets find out the 3rd term

Substitute n = 3

$a_{3} = 2\cdot 4^{3-1} = 2\cdot 4^{2} = 2\cdot 16 = 32$

Lets find out the 4th term

Substitute n = 4

$a_{4} = 2\cdot 4^{4-1} = 2\cdot 4^{3} = 2\cdot 64 = 128$

Lets find out the 5th term

Substitute n = 5

$a_{5} = 2\cdot 4^{5-1} = 2\cdot 4^{4} = 2\cdot 256 = 512$

Hence, we are getting correct results!

6 0

3 years ago

Hamburgers cost $2 and hotdogs cost $2. The total cost of buying b hamburgers and d hotdoge can be expressed by C=3b+2d. how can

sveticcg [70]

C= 3b + 2d
Subtract 3b first.

C-3b = 2d
Divide by 2.

C-3b/2 = d

OR

C-3b
-------- = d Your final answer!
2

3 0

3 years ago

Find the values of x and y

zhuklara [117]

You can use a tangent:

$tangent=\dfrac{opposite}{adjacent}$

We have opposite = 17 and adjacent = x.

$\tan30^o=\dfrac{\sqrt3}{3}$

substitute:

$\dfrac{17}{x}=\dfrac{\sqrt3}{3}$ cross multiply

$x\sqrt3=(3)(17)$ multiply both sides by √3

$x(\sqrt3)(\sqrt3)=51\sqrt3$

$3x=51\sqrt3$ divide both sides by 3

$x=17\sqrt3$

Use the Pythagorean theorem:

$y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34$

-------------------------------------------------------------------------------------------------

Other method.

$30^o-60^o-90^o$ triangle.

The sides are in the ratio $1:2:\sqrt3\to17:y:x$

Therefore

$17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3$

4 0

3 years ago