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Nadusha1986 [10]
3 years ago
7

What is 7% as a decimal?

Chemistry
1 answer:
Colt1911 [192]3 years ago
6 0
.07! you divide 7 by 100%


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For each pair of covalently bonded atoms, choose the one expected to have the shortest bond length. (A) C-I (B) H-I ...... (A,B)
UNO [17]

Answer:

i)  B

ii) D

Explanation:

<em>Bond length is determined by the size of the atoms involved and the bond order </em>

A) C-I

B)  H-I

answer : H-I has the shortest bond length because H has an electronegativity value of 2.2  while C has an electronegativity value of 2.5 hence the bond between H-I is greater than C - I due the electronegativity difference between H-I is greater as well.

C) H-Cl

D) H-I

answer :  H-Cl has the shortest bond length due the electronegativity difference between H-CI is greater as well.

8 0
2 years ago
Which metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe?
Pepsi [2]

manganese The metal that is used as a sacrificial electrode to prevent the rusting of iron is manganese.

8 0
3 years ago
What are the 3 types of weathering
givi [52]
Chemical, physical, and biological 
are the three types of weathering
Hope this helped!!
3 0
2 years ago
Read 2 more answers
Consider the following balanced equation:
Serga [27]
<span>Zn⁰ + 2H⁺ ------> Zn²⁺ + H2⁰

H⁺ ion has oxidation number +1.
Zn²⁺ ion has oxidation number +2.
Atom of Zn has electric charge 0, and each hydrogen atom in the molecule H2 have oxidation number 0. So, </span> Zn and each hydrogen atom in H2 have oxidation numbers equals "0".<span>

</span><span>Answer is
D. Zn and each hydrogen atom in H2</span><span>

</span>
4 0
3 years ago
Suppose a student titrates a 10.00-ml aliquot of saturated ca(oh)2 solution to the equivalence point with 16.08 ml of 0.0199 m h
Alborosie
Following chemical reaction is involved upon titration of Ca(OH)2 with HCl,
Ca(OH)2 + 2HCl ↔ CaCL2 + 2H2O

Above is an example of acid-base titration to generate salt and water. Here, H+ ions of acid (HCl) combines with OH- (ions) of base [Ca(OH)2] to generated H2O

Given,
concentration of HCl = 0.0199 M
Total volume of HCl consumed during titration = 16.08 mL = 16.08 X 10^(-3) L

∴, number of moles of H+ consumed = Molarity X Vol. of HCl (in L)
                                                           = 0.0199 X 16.08 X 10^(-3)
                                                           = 3.1999 X 10^-4 mol
Thus, total number of moles of [OH-] ions present initial = 3.1999 X 10-4 mol
So, initial conc. [OH-] ion = 
\frac{number of moles of [OH-]}{volume of solution (L)} = \frac{3.1999 X 10^(^-^4^)}{10 X 10^(^-^3^)} = 0.03199 M
6 0
3 years ago
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