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Ann [662]
3 years ago
9

According to the law of conservation of energy, the energy released by the system must be transferred to and absorbed by the sur

roundings
Chemistry
1 answer:
Andrew [12]3 years ago
5 0
True! 
 Energy released by system is absorbed by surroundings.
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A ____________ alkene is more stable than a ____________ alkene because they have fewer steric interactions. In an elimination r
Vesna [10]

Answer:

See explanation

Explanation:

A <u>trans</u> alkene is more stable than a <u>cis alkene</u> because they have fewer steric interactions.

<em>⇒ In a cis alkene there is steric hindrance, because the methyl groups are on the same side of the double bond. </em>

<em>Because of this steric crowding, there are van der Waals repulsive forces between the electron clouds of the groups. </em>

<em> </em>

<em>This decreases the stability of the cis alkene.</em>

<em />

In an elimination reaction, a geometry where the β hydrogen and the leaving group are on opposite sides of the molecule is called <u>anti</u> periplanar.

<em> ⇒ 'Anti’ refers to the two functional groups lying on opposite sides of the plane of the bond</em>

In an <u>SN1 </u>mechanism, a nucleophile attacks the carbocation, forming a substitution product,

<em> ⇒ The SN1 reaction is a substitution reaction, and means "nucleophilic substitution".The "1" says that the rate-determining step is unimolecular. Thus, the rate equation is often shown as having first-order dependence on electrophile and zero-order dependence on nucleophile.</em>

while in an <u>E1</u><u> </u>mechanism, a base removes a β hydrogen from the carbocation, forming a new π-bond.

<em> ⇒ E1 indicates a elimination, unimolecular reaction</em>

<em>This implies that the rate determining step of the mechanism depends on the decomposition of a single molecular species.</em>

<em>.This is a classic elimination reaction – forming a new C–C(π) bond, and breaking a C–H and C–leaving group bond.</em>

CH3CH2Br and NaOH react by an <u>SN2</u><u> </u>mechanism.

<em> ⇒  It's a type of reaction mechanism that is common in organic chemistry, where one bond is broken and one bond is formed, synchronously, (in one step.) </em>

Stronger bases, like hydroxide, favor<u> E2</u> reactions, whereas weaker bases, like water favor, <u>E1</u> reactions

Disubstituted alkenes always have the possibility to exist as two different <u>Diastereomer.</u>

<em>Diastereomer are stereoisomers that are not mirror images of one another and are non-superimposable on one another. They exist (always) in 2 forms.</em>

<u>Elimination reactions</u> are regioselective, favoring formation of the more substituted and more stable alkene.

6 0
3 years ago
If 31.6 g of KMnO4 is dissolved in enough water to give 160 mL of solution, what is the molarity?
Zina [86]

Answer:

A. 1.25M

B. 19.98g

Explanation:

A. Data obtained from the question include the following:

Mass of KMnO4 = 31.6 g

Volume = 160 mL

Molarity =..?

We'll begin by calculating the number of mole KMnO4 in the solution. This is can be obtained as follow:

Mass of KMnO4 = 31.6 g

Molar mass of KMnO4 = 39 + 55 + (16x4) = 158g/mol

Number of mole of KMnO4 =..?

Mole = mass /Molar mass

Number of mole of KMnO4 = 31.6/158 = 0.2 mole

Now, we can obtain the molarity of the solution as follow:

Volume = 160 mL = 160/1000 = 0.16L

Mole of KMnO4 = 0.2 mole

Molarity = mole /Volume

Molarity = 0.2/0.16 = 1.25M

B. Data obtained from the question include the following:

Volume = 300mL

Molarity = 0.74 M

Mass of H2C2O4 =..?

First, we shall determine the number of mole H2C2O4. This is illustrated below:

Volume = 300mL = 300/1000 = 0.3L

Molarity = 0.74 M

Mole of H2C2O4 =?

Mole = Molarity x Volume

Mole of H2C2O4 = 0.74 x 0.3

Mole of H2C2O4 = 0.222 mole

Now, we can easily find the mass of H2C2O4 by converting 0.222 mole to grams as shown below:

Number of mole of H2C2O4 = 0.222 mole

Molar mass of H2C2O4 = (2x1) + (12x2) + (16x4) = 2 + 24 + 64 = 90g/mol

Mass of H2C2O4 =..?

Mass = mole x molar mass

Mass of H2C2O4 = 0.222 x 90

Mass of H2C2O4 = 19.98g

5 0
3 years ago
Manganese-56 is a beta emitter with a half-life of 2.6 hours. What is the mass of
Arisa [49]

Answer:

0.0009765625

Explanation: u just keep doing a half life till it goes to 13 aka

8.0g divided by 2  till you reach to 13 times of a half life ;p

8 0
3 years ago
Read 2 more answers
How many joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point?
Korolek [52]

Answer: 1123000 Joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point

Explanation:

Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.

Amount of heat required to vaporize 1 mole of lead =  177.7 kJ

Molar mass of lead = 207.2 g

Mass of lead given = 1.31 kg = 1310 g       (1kg=1000g)

Heat required to vaporize 207.2 of lead = 177.7 kJ

Thus Heat required to vaporize 1310 g of lead =\frac{177.7}{207.2}\times 1310=1123kJ=1123000J

Thus 1123000 Joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point

7 0
3 years ago
A catalyst can speed up the rate of a given chemical reaction by
hjlf

Decreasing the activation energy needed for the reaction.

4 0
3 years ago
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