In the following balanced neutralization reaction equation, how many moles of Ca(OH)2 are required to completely neutralize 1.2

Question

3 years ago

13

moles of HI? 2HI + Ca(OH)2 → CaI2 + 2H2O

2 answers:

Roman55 [17] · Answer 1 · 2022-07-14T15:00:58+03:00

5 0

0.6 moles is the answer

denis-greek [22] · Answer 2 · 2022-07-14T16:30:42+03:00

Answer : The number of moles of $Ca(OH)_2$ required are, 0.6 mole.

Explanation : Given,

Moles of HI = 1.2 moles

The given balanced chemical reaction is,

$2HI+Ca(OH)_2\rightarrow CaI_2+2H_2O$

From the balanced chemical reaction, we conclude that

As, 2 moles of $HI$ react with 1 mole of $Ca(OH)_2$

So, 1.2 moles of $HI$ react with $\frac{1.2}{2}=0.6$ mole of $Ca(OH)_2$

Therefore, the number of moles of $Ca(OH)_2$ required are, 0.6 mole.