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elena55 [62]
3 years ago
11

Watersheds are sloped areas of land that ?

Chemistry
2 answers:
luda_lava [24]3 years ago
8 0
A. Channel precipitation runoff into bodies of water.
nikitadnepr [17]3 years ago
8 0
The answer is A, hope it helps
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Which change will always take place during nuclear fission?
Aleks04 [339]

Answer:

um pretty sure this is it

Explanation:

The fission process also releases extra neutrons, which can then split additional atoms, resulting in a chain reaction that releases a lot of energy.

5 0
2 years ago
Give two examples in your everyday experience where diffusion occurs. Can you think of a situation of where this might be harmfu
Vesnalui [34]
The first example of diffusion is smoking a cigarette when u light it it spreads through the air. 
The second example is lighting a candle in a room it the smoke spreads through the air. 
Smoke can be very bad for the air and the people around because it can cause many problems with your breathing. 
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3 years ago
How are rotation and day related?
Nadya [2.5K]
When earth turns once it's a day
3 0
3 years ago
At equilibrium, the concentrations in this system were found to be [ N 2 ] = [ O 2 ] = 0.200 M and [ NO ] = 0.600 M . N 2 ( g )
alexandr1967 [171]

Answer:

0.78 M

Explanation:

First, we need to know which is the value of Kc of this reaction. In order to know this, we should take the innitial values of N2, O2 and NO and write the equilibrium constant expression according to the reaction. Doing this we have the following:

N2(g) + O2(g) <------> 2NO(g)   Kc = ?

Writting Kc:

Kc = [NO]² / [N2] * [O2]

Replacing the given values we have then:

Kc = (0.6)² / (0.2)*(0.2)

Kc = 9

Now that we have the Kc, let's see what happens next.

We add more NO, until it's concentration is 0.9 M, this means that we are actually altering the reaction to get more reactants than product, which means that the equilibrium is being affected. If this is true, in the reaction when is re established the equilibrium, we'll see a loss in the concentration of NO and a gaining in concentrations of the reactants. This can be easily watched by doing an ICE chart:

      N2(g) + O2(g) <------> 2NO(g)

I:      0.2        0.2                 0.9

C:     +x         +x                   -2x

E:    0.2+x    0.2+x             0.9-2x

Replacing in the Kc expression we have:

Kc =  [NO]² / [N2] * [O2]

9 = (0.9-2x)² / (0.2+x)*(0.2+x)   ----> (this can be expressed as 0.2+x)²

Here, we solve for x:

9 = (0.9-2x)² / (0.2+x)²

√9 = (0.9-2x) / (0.2+x)

3(0.2+x) = 0.9-2x

0.6 + 3x = 0.9 - 2x

3x + 2x = 0.9 - 0.6

5x = 0.3

x = 0.06 M

This means that the final concentration of NO will be:

[NO] = 0.9 - (2*0.06)

[NO] = 0.78 M

8 0
3 years ago
In examining an organic compound, you discover that it contains the following functional group. What class of organic compound i
Romashka [77]
Option B. carboxylic acid

For example

CH3 - COOH, is the acetic acid or etanoic acid.

where - COOH is C bonded with O (trhough doble bond) and with OH (with a single bond)
8 0
3 years ago
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