Question

The condensed electron configuration of vanadium, element 23, is ________. a. [Ar]3s23p7 b. [Ar]3s43p5 c. [Ne]3s43p3 d. [Ne]3s43p1 e. [Ar]3d34s2

Answer 1

Answer: Vanadium -23 has an electronic configuration of

[Ar]3d3 4s2 (e)

Explanation:

Vanadium has an atomic number of 23 . The total number of electrons in all the subshells will also be 23 .

For (a) [ Ar] has an 18 electrons already, adding 2 from 3s subshell 7 from 3p subshell makes it 27 electrons which is greater than 18. Also, it doesn't conform with the rule of electronic configuration.

(b) [ Ar] has an 18 electrons already, adding, adding 4 from 3s orbital and 5 from 3p orbital makes it 27 which is greater than 23.

(c) [ Ne] has an 10 electrons already, adding, 3 from 3s and 3 from 3p makes it 16. Which is less than 23

(d) [ Ne] has an 10 electrons already, adding, 4 from 3s and 1 from 3p makes it 14 . Which is less than 23.

(e)[ Ar] has an 18 electrons already, adding, 3 from 3d subshell and 2 from 4s subshell makes it 23.

Therefore [Ar]3d3 4s2 is the condesed electronic configuration of Vanadium.