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Y_Kistochka [10]
3 years ago
14

Khi cho anken phản ứng với nước có thể tạo ra ancol bậc

Chemistry
1 answer:
Nitella [24]3 years ago
6 0

Answer:

yes

CH3- CH2=CH2 + H2O —> CH3-CH3-CH2-OH

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8.3 miles of sodium chloride in 0.65 of water.
Allisa [31]

Answer:

12.77 M

Explanation:

8.3 moles of NaCl in .65 L of water ?    Looking for M ?

8.3 M / .65 L  =  12.77 M

4 0
2 years ago
The lock-and-key model and the induced-fit model are two models of enzyme action explaining both the specificity and the catalyt
ivolga24 [154]

Answer:

The lock-and-key model:

c. Enzyme active site has a rigid structure complementary

The induced-fit model:

a. Enzyme conformation changes when it binds the substrate so the active site fits the substrate.

Common to both The lock-and-key model and The induced-fit model:

b. Substrate binds to the enzyme at the active site, forming an enzyme-substrate complex.

d. Substrate binds to the enzyme through non-covalent interactions

Explanation:

Generally, the catalytic power of enzymes are due to transient covalent bonds formed between an enzyme's catalytic functional group and a substrate as well as non-covalent interactions between substrate and enzyme which lowers the activation energy of the reaction. This applies to both the lock-and-key model as well as induced-fit mode of enzyme catalysis.

The lock and key model of enzyme catalysis and specificity proposes that enzymes are structurally complementary to their substrates such that they fit like a lock and key. This complementary nature of the enzyme and its substrates ensures that only a substrate that is complementary to the enzyme's active site can bind to it for catalysis to proceed. this is known as the specificity of an enzyme to a particular substrate.

The induced-fit mode proposes that binding of substrate to the active site of an enzyme induces conformational changes in the enzyme which better positions various functional groups on the enzyme into the proper position to catalyse the reaction.

4 0
3 years ago
Which of the following trends can be identified on the periodic table?
Jet001 [13]

Answer:

D) atomic radii increase from top to bottom of a group

Explanation:

Atomic radii trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

Other options are incorrect because,

A) atomic radii increase from left to right across the period

Correct = atomic radii decreases from left to right across the period

B) ionization energy increases from top to bottom within a family

Correct =  ionization energy decreases from top to bottom within a family

C) electronegativity decreases from left to right across a period

Correct = electronegativity increases from left to right across a period

8 0
3 years ago
Convert .004569g to mg
algol [13]

Answer:

4.569 mg

:)))))))))))))))

4 0
3 years ago
Read 2 more answers
Protein x has an absorptivity of 0.4 ml·mg-1 ·cm-1 at 280 nm. What is the absorbance at 280 nm of a 2.0 mg ·ml-1 solution of pro
Evgen [1.6K]

Absorbance measures the ability of the substance to absorb light at a specific wavelength.

Absorbance is also equal to the product of molar absorptivity, path length and molar concentration.

The mathematical expression is given as:

A= \epsilon l c       (1)

where, A = absorbance

\epsilon =  molar absorptivity

l = path length

c  = molar concentration.

The above formula is said to Beer's Law.

Absorptivity of protein x  = 0.4 mLmg^{-1}cm^{-1}

Path length = 1 cm

Molar concentration = 2.0 mg mL^{-1}

Put the values in formula (1)

Absorbance at 280 nm = 0.4 mL mg^{-1}cm^{-1}\times 1 cm \times 2.0 mg mL^{-1}

= 0.8

Thus, absorbance at 280 nm = 0.8

3 0
3 years ago
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