Consider the equation y = 2x + 3. Drag the red point on the graph to represent the

Solve the system by substitution.<br> -8x – 7y = -5<br> -x = y

Lapatulllka [165]

Substitute y = -x into the first equation:

-8x - 7(-x) = -5

-8x + 7x = -5

-x = -5

x = 5

Substitute x = 5 into y = -x

y = -(5)

y = -5

Answer: x = 5, y = -5

6 0

3 years ago

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Factorization 36+121c2+132c

Sliva [168]

Answer:

(6+11c)^2

hope this helps :)

5 0

4 years ago

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Plsssss helppppppp because I am v confused

Allisa [31]

The simplified version of this expression is 110g^4h^16v^6. first, remove the parenthesis. the expression becomes 10g^3h^8v^6 times 11gh^8. then, calculate the product.

4 0

3 years ago

5. Explain how you could use compatible numbers to estimate 245 ÷ 3. Then estimate the quotient.

sdas [7]

Answer:

8

Step-by-step explanation:

Compatible numbers are defined as the numbers which are very close to the numbers that they are replacing that divides evenly into each other.

In the context, we have to estimate the quotient using the compatible numbers in order to estimate 245 divided by 3.

So, estimating 245 as 240 and 3 as 30.

Here, 240 is very close to 245 and 30 is close to 3. So the quotient is the result when we divide 240 by 30 and it divides evenly into 240.

We first divide the non zero parts of each number i.e. 24 by 3 to get the first part of the estimate.

Then we add on the zero if there were left in the problem to get your estimate.

Therefore,

240 / 30 = 8

So here, the quotient is estimated as 8.

4 0

3 years ago

Find the common fraction equivalent to 0.12

jonny [76]

The answer is: " $\frac{4}{33}$ "  .
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Given: 0.1212121212..... repeating ; write that value as a fraction;
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In other words; we are given: "0.1212121212..... repeating infinitely" ;

→ that is to say; "0.12 ... ; {the "12" decimal portion repeats infinitely} ;
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→ We write this value, as a fraction, as: "12/99" ;
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→Explanation:
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Note: "0.99999999...... repeating infinitely; = "1" .
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→Since:

Let us say that we have:

"x = 0.999999 ; repeating infinitely;

In order words, let us say we have: "x = 0.9.... ; the "9" decimal repeats infinitely;
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Then "10x" ; (that is: "10" multlipled by "x"; or "10*x" or "10x" ); is equal to:

"10" * (0.999999.....) = 9.99999999...... (the "9" decimal repeats infinitely);

in other words: 10x = 9.99999999....

Divide each side by "10" ;

to get "x = 0.9999999....." ; the decimal "9" repeats indefinitely...." ;

But if you have: "10x = 10" ; divide each side of the equation by "10" ;
you get: "x = 1" .
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Also, if "x = 0.9999...(repeating infinitely);

then: 10x = 9.99999.
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10x = 9.999999999999999......
−   x = 0.999999999999999.......
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9x = 9.00000000000000000000.....

→ 9x = 9 ;

Divide each side of the equation; to get;

9x /9 = 9/ 9 ; to get: x = 1 ; and we have: x = 0.9999.... ; so
x= 0.99999.... = 1 ;
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So, if the numbers "12" is repeating, we divie "12" by "99" ;
that is; we divide "12" by "two 9's" ; since "12" is a "TWO-digit number"; a "two-digit number" is being repeated infinitely.
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So; 0.12121212.....(the "12" is the decimal that repeats infinitely);

= 12/99 ; which can be simplified;

Divide each side (both the numerator AND the denominator); by "3" ;
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" 12/99 " = "(12÷3) / (99÷3) = 4/33 " .
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The answer is: $\frac{4}{33}$   .
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8 0

3 years ago

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