Answer:
Profit % =50%
Step-by-step explanation:
Cost of 50 kg = sh 4000
Selling price of 1kg = sh 120
Selling price of 50 kg = sh 6000
Answer:
<h3>444m</h3>
Step-by-step explanation:
Given the height of the rocket modelled by the equation;
y=-16x^2+152x+83
The rocket reaches its maximum height when the velocity of the rocket is zero.
Since velocity is the change in displacement with respect to time;
velocity v = dy/dx
dy/dx = -32x + 152
at dy/dx = 0
-32x + 152 = 0
-32x = -152
x = -152/-32
x = 4.75s
To get maximum height reached by the ball, we will substitute x = 4.75 into the modeled function as shown;
y(4.75) = -16(4.75)^2+152(4.75)+83
y(4.75) = -361+722+83
y(4.75) = 444m
Hence the maximum height reached by the ball is 444m
Answer:
y=-2x-20y=−2x−20
Step-by-step explanation:
best models the line of best fit for the data
(5 / 3) * PI = 300 degrees
Sector area = (central angle (degrees) / 360) * PI * radius^2
Sector area = (300 / 360) * 3.14 * 36
Sector area = (5/6) * 3.14 * 36
Sector area = 30 * 3.14
Sector area = 94.2 square feet
Source: http://www.1728.org/radians.htm
