Pi=3.14
m=6 g=0.006 kg
r=5 cm =0.05 m
h=2 cm=0.02 m
volume_of_cone=pi*r^2*h/3 = 5.23599*10^-5=5.24E-5
p=m/v
p=(0.006/(5.24E-5))=1.14503817*10^-8=1.14503817e-8
$22,000 * 0.12 = $2,640
so
$22,000 - $2,640 = $19,360
so
$19,360 after 1 year.
$19,360 * 0.12 = $2,323.20
$19,360 - $2,323.20 = $17,036.80 (2 years)
$17,036.80 * 0.12 = $2,044.416
Don't round until you finish the problem.
$17,036.80 - $2.044.416 = $14,992.384 (3 years)
$14,992.384 * 0.12 = $1,799.08608
$14,992.384 - $1,799.08608 = $13,193.29792 (4 years)
ROUND
$13,193.29792 rounded to $13,193.30
Differentiating the function
... g(x) = 5^(1+x)
we get
... g'(x) = ln(5)·5^(1+x)
Then the linear approximation near x=0 is
... y = g'(0)(x - 0) + g(0)
... y = 5·ln(5)·x + 5
With numbers filled in, this is
... y ≈ 8.047x + 5 . . . . . linear approximation to g(x)
Using this to find approximate values for 5^0.95 and 5^1.1, we can fill in x=-0.05 and x=0.1 to get
... 5^0.95 ≈ 8.047·(-0.05) +5 ≈ 4.598 . . . . approximation to 5^0.95
... 5^1.1 ≈ 8.047·0.1 +5 ≈ 5.805 . . . . approximation to 5^1.1
1 wallet= 5/32= 0.15625
Wallets for $80= 0.15625*80=12 wallets