The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2
Take y=0 then,
=> 2
=0
=>
=0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
brainly.com/question/24147137
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Answer: Exponential growth
There will be 5ounces of peanut butter for every pound of jelly
Answer:
what grade are you in so then I could get the answer
So pythagrorean theorem is the ideal way and easiest way to solve this
a^2+b^2=c^2
8.5^2+11^2=x^2
72.25+121=193.25
square root of 193.25=13.9014 or 13.9 in
9.5^2+15^2=x^2
90.25+225=315.25
square root of 315.25=17.7553 or 17.8 ft