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masya89 [10]
3 years ago
12

How can electromagnetic waves be used to fight a forest fire

Physics
2 answers:
-Dominant- [34]3 years ago
6 0

Answer:

Explanation:

Electromagnetic waves can be used to fight a forest fire by using infrared images. These scanner can show the hot spots that represent fire. This can help to locate a fire in a dark clouds that envelope a place you can’t see.

Is wrong!!!

Answer is B

PSYCHO15rus [73]3 years ago
5 0
Electromagnetic waves can be used to fight a forest fire by using infrared images. These scanner can show the hot spots that represent fire. This can help to locate a fire in a dark clouds that envelope a place you can’t see.
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PLEASE HELP!! WILL GIVE POINTS
AURORKA [14]

Answer:

49 kg is the mass of the couch.

Explanation:

GPE = mgh

9800 = m * 10 * 20

9800 = 200m

m = (9800/20) = 49 m

Thenks and mark me brainliest :))

3 0
4 years ago
Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They
mamaluj [8]

Answer:

Explanation:

a net force of F causes a cart with a mass of M to accelerate at 48 cm/s/s.

F = M x 48

Mass M = F / 48

a )

When force = 2F and mass = M

Acceleration = force / mass

= 2F /F/48

= 48 X 2 = 96 cm/s²

b )

When force = F and mass = 2M

Acceleration = force / mass

= F /2F/48

=  24 cm/s²

c )

When force = 2F and mass = 2M

Acceleration = force / mass

= 2F /2F/48

=  48  cm/s

d )

When force = 2F and mass = 4M

Acceleration = force / mass

= 2F /4F/48

=  24  cm/s

e)

When force = 4F and mass = 2M

Acceleration = force / mass

= 4F / 2M

= 4F / 2 F/48

= 48 x 2

Acceleration  = 96 cm/s²

7 0
4 years ago
A radio wave sent from the surface of the earth reflects from the surface of the moon and returns to the earth. The elapsed time
frez [133]

Answer:

7.92 × 10^8 M

8 0
4 years ago
Chapter 05, Problem 15 Multiple-Concept Example 7 and Concept Simulation 5.2 review the concepts that play a role in this proble
Llana [10]

Answer:

Explanation:

The question relates to motion on a circular path .

Let the radius of the circular path be R .

The centripetal force for circular motion is provided by frictional force

frictional force is equal to μmg , where μ is coefficient of friction and mg is weight

Equating cenrtipetal force and frictionl force in the case of car A

mv² / R = μmg

R = v² /μg

= 26.8 x 26.8 / .335 x 9.8

= 218.77 m

In case of moton of car B

mv² / R = μmg

v²  = μRg

= .683  x 218.77x 9.8

= 1464.35

v = 38.26 m /s .

3 0
3 years ago
A moving company collects data about couches they move and displays the data in a table. The force along the ramp, the angle of
USPshnik [31]

Answer:

the correct answers are d, e, & f

Explanation:

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7 0
4 years ago
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