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WINSTONCH [101]
2 years ago
13

6. Most organizations have not banned the use of performing enhancing drugs.

Physics
1 answer:
Setler79 [48]2 years ago
4 0
The answer is false
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Hello everyone. This is a question about Dimensional Analysis and I came across this question but I am unable to wrap my head ar
omeli [17]

Answer:

2. [B] = [L]/[T] and [C] = [L]/[T]

Explanation:

I assume you mean this:

A = B² + 2B⁴/C²

Since you can't add numbers with different units (for example, you can't add seconds to meters), each term in the sum must have the same units as A.

B² = [L]²/[T]²

B = [L]/[T]

B⁴/C² = [L]²/[T]²

C²/B⁴ = [T]²/[L]²

C² = B⁴ [T]²/[L]²

C² = ([L]/[T])⁴ [T]²/[L]²

C² = [L]²/[T]²

C = [L]/[T]

Notice we ignore the 2 coefficient, which is unitless.

7 0
3 years ago
El Niño occurs every 2 to 12 years. true false
Novosadov [1.4K]
True
It is True I took the test
5 0
3 years ago
Read 2 more answers
You are holding a positive charge and there are positive charges of equal magnitude 1 mm to your north and 1 mm to your east. Wh
lara [203]

If I hold a positive charge in my hand and there are positive charges of equal magnitude 1 mm to your north and 1 mm to your east then the direction of the force on the charge I am holding is towards the north-east direction.

Reasoning:

It is given that there is a positive charge in my hand. There are two more positive charges with the same magnitude. One is 1 mm far towards the east, and the other one is 1 mm far towards the north. It is required to find the direction of the force acting on the charge in my hand.

Let the magnitude of the charge in my hand is Q, and the magnitude of the other charges is q.

Thus the electric force applied on the charge in my hand due to each other is,

F=\frac{kQq}{r^2}

Here k is the Coulomb constant, and r is the distance between the charges.

It is also known that the force on a positive charge due to another positive charge is acted outwards.

Thus, the force on the charge due to the charge on the east is,

\vec{F_1}=\frac{kQq}{( 10^{-3}\text{ m})^2}\hat{i}

And the force on the charge due to the charge on the north is,

\vec{F_2}=\frac{kQq}{( 10^{-3}\text{ m})^2}\hat{j}

As the forces are equal in magnitude and one is perpendicular to the other, thus the net force will be acted at an angle of 45^\circ from the north or from the north direction.

Thus the net force is acting in the north-east direction.

Learn more about the direction of the force here,

brainly.com/question/2037071

#SPJ4

3 0
2 years ago
If I traveled 30 miles in 1 hour, then 20 miles in 1 hour, and 50 miles in 3
Harrizon [31]

Answer:

The answer is 20 miles/hr

Explanation:

5 0
3 years ago
Does the temperature of a material always increase as it is heated? Explain briefly.
Lerok [7]
To answer your question, no,
temperature does not always increase as it is heated. Adding heat does not always increase the temp.
For example, when water is boiling, adding heat does not increase the temperature. This occurs at the boiling temp of every substance that can vaporize. 

Hope this explanation was helpful and brief! :)
6 0
3 years ago
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