Kinetic Energy = 1/2mv^2
m= 1200kg
v= 24 m/s
KE = 1/2 (1200kg)(24m/s)^2 = 345,600 N
A. Neutrons.
If it were electrons, it would be an ion.
If it were protons, it wouldn't be the same element.
A) The power delivered to the lines is

And the voltage at which the lines work is

Since the power delivered is the product between the voltage and the current:

We can find the current flowing in the lines:

b) The voltage change along each line can be found by using Ohm's law:

c) The power wasted as heat along each line is given by:

And since we have 2 lines, the total power wasted as heat in both lines is
Answer:
m = 3.9 [m³]
Explanation:
We must remember that the density of the substance is defined as the relationship between mass over volume. That is expressed in the following equation:

where:
Ro = density = 1.3 [kg/m³]
m = mass [kg]
V = volume = 3 [m³]
Now replacing the values.
![m =Ro*V\\m = 1.3*3\\\\m=3.9[m^{3}]](https://tex.z-dn.net/?f=m%20%3DRo%2AV%5C%5Cm%20%3D%201.3%2A3%5C%5C%5C%5Cm%3D3.9%5Bm%5E%7B3%7D%5D)